The sum of consecutive integers 1,2,3,...,n is given by the formula 1/2n(n+1). How many consecutive integers, starting with 1, m
ust be added to get the sum of 1081
1 answer:
1/2 * n * (n+1) = 1081
distribute
1/2 n^2 +1/2n -1081=0
factor out 1/2
1/2 (n^2 +n -2162) =0
multiply each side by 2
(n^2 +n -2162) =0
factor
(n-46) (n+47) =0
n=46, n=-47
n cannot be negative
n=46
Answer 46
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