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svetoff [14.1K]
4 years ago
10

Find an equation of the tangent line to the curve at the given point. y = 7x + 9 cos(x), p = (0, 9)

Mathematics
1 answer:
labwork [276]4 years ago
6 0

Alright, lets get started.

We have given a curve y, and a point P.

y = 7x + 9 cosx

The derivative of the curve is the slope of the tangent line.

We will find the derivative of the given function.

\frac{dy}{dx}  = \frac{d}{dx}(7x + 9 cos x)

\frac{dy}{dx} = 7 + 9 (-sin x)

\frac{dy}{dx}  = 7 - 9 sin x

Putting the value as x = 0 because P (0,9)

\frac{dy}{dx}  = 7 - 9 sin 0

As sin 0 = 0

\frac{dy}{dx} = 7 - 0

\frac{dy}{dx}  = 7

The equation of tangent will be : y =mx + c where m is slope

y = 7 x + c

Putting the value of (x,y) as (0,9), we could find the value of c

9 = 7 * 0 + c

c = 9

Hence the equation of tangent will be :

y = 7 x + 9

Answer

Hope it will help :)

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