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3 years ago

Rewrite the expression by using symbols 7(x - 20)

Mathematics

1 answer:

Lelechka [254]3 years ago

5 0

7 × x - 7 × 20

You could rewrite it this way, 7 x (x-20), but the answer above is better 'cause it takes away the grouping symbols

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The midpoint of AB is M(3,1).If the coordinates of A are (8,4) what are the coordinates of B

gulaghasi [49]

Answer:

The coordinates of B are (-2 , 9)

Step-by-step explanation:

A (8, 4)

M (3 , -1)

To calculate a midpoint you have to add the corresponding coordinates of each point and divide them by 2

(Ax + Bx) / 2 = Mx

(8 + Bx) / 2 = 3

8 + Bx = 3 * 2

Bx = 6 - 8

Bx = -2

(Ay + By) / 2 = My

( -1 + By) / 2 = 4

-1 + By = 4 * 2

By = 8 + 1

By = 9

The coordinates of B are (-2 , 9)

4 0

4 years ago

An Astronaut drops a rock into crater on the moon. The distance,d(t), in meters, the rock travels after t seconds can be modeled

OlgaM077 [116]

speed =distance traveled over time taveled... the ansewr will be in kilometres per hour

4 0

3 years ago

Find the face value of the 20-year zero-coupon bond at 4.4%, compounded semiannually, with a price of $8,375.

umka21 [38]

<u>Given</u>:

Time,

t = 20 years

Rate,

r = 4.4%

Price

= $8,375

Now,

The yield will be:

= $\frac{4.4}{2}$

= $1.1$ (%)

Time will be:

= $20\times 2$

= $40 \ periods$

As we know the formula,

⇒ $Price \ of \ bond = \frac{Face \ value}{(1+\frac{r}{2} )^{n\times 2}}$

By substituting the values, we get

$8375=\frac{Face \ value}{(1+\frac{0.044}{2} )^{20\times 2}}$

$8375=\frac{Face \ value}{(1.022)^{40}}$

$8375=\frac{Face \ value}{2.3880083}$

The face value will be:

$Face \ value = 2.3880083\times 8375$

$=20,000$ ($)

Learn more about face value here:

brainly.com/question/14862802

5 0

3 years ago

The 13th term of a geometric sequence is 16, 384 and the first term is 4. What is the common ratio?

AleksAgata [21]

Answer:

$\large \boxed{2}$

Step-by-step explanation:

The formula for the nth term of a geometric sequence is

aₙ = a₁rⁿ⁻¹

In your geometric sequence, a₁ = 4 and a₁₃ = 16 384.

$\begin{array}{rcl}16384 & = & 4r^{(13 - 1)}}\\16384 & = & 4r^{12}\\4096 & = & r^{12}\\3.6124 & = & 12 \log r\\0.30102 & = & \log r\\r & = & 10^{0.30102}\\ & = & \mathbf{2}\\\end{array}\\\text{The common ratio is $\large \boxed{\mathbf{2}}$}$

Check:

$\begin{array}{rcl}16384 & = & 4(2)^{12}\\16384 & = & 4(4096)\\16384 & = & 16384\\\end{array}$

It checks.

7 0

3 years ago

borishaifa [10]

5
hope this helped!!!!!!!

3 0

3 years ago