Let us assume for starters that it is true.
The area of the square is s^2, so that is where you start.
(1 + 2*sqrt(2) ) ^2 = 1 + 4*sqrt(2) + 8 Taking 1 away form that does not leave you with 8.
Let's start again.
If all sides are reduced by 1 , but the square is retained, then the length of the side is 2sqrt(2). Now we have
s^2 = (2sqrt(2) )^2 = 4 * 2 = 8
The question is really not worded clearly enough to give an answer. I think it's true, but the language has to be twisted a bit.
Answer: I'd answer true, but don't be surprised if it is not interpreted the way I did on my second try.
The last pair of numbers bracket the point 3/7.
12/32 = 3/8 < 3/7
15/18 = 5/6 > 3/7
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3/7 ≈ 0.428571... (repeating), so will be larger than 3/8 = 0.375, 12/32 = 3/8, and 4/10. That is, 3/7 is larger than the largest number of each pair except the last.
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You can always compare two fractions to see which is larger by cross-multiplying. That is a/b vs c/d gives the same result as ad vs bc. (Put the product on the numerator side of the comparison.)
Here, that would mean comparing 12/32 vs 3/7, we would get 12·7 vs 3·32, or 84 vs 96. The fraction on the left is smaller.
Comparing 3/7 vs 15/18, we would get 3·18 vs 7·15, or 54 vs 105. The fraction on the right is larger.
How is anyone supposed to answer this?
Answer:
11 in = 33 in.
Step-by-step explanation:
6 in. = 18 in.
the second triangle is 3 times bigger than the smaller one.
Answer:
6,12,12 square root 3
Step-by-step explanation:
