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eimsori [14]
2 years ago
14

Emanuel read 150 pages in 5 hours. Find his average reading rate.

Mathematics
1 answer:
Zina [86]2 years ago
7 0

Answer:

30 pages per hour

Step-by-step explanation:

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A rectangular prism with the volume of 10 cubic units is filled with cubes with side links of 1/2 unit how many 1/2 unit kids do
ELEN [110]
Answer 80
Required cubes 10/1/8=80
8 0
3 years ago
HELP ASAP PLSSSSSSSSSSSS
ludmilkaskok [199]

Answer:

f = .39

Step-by-step explanation:

d (v) = 2.15 v^2 / (64.4 f)

v = 40

d = 138

substitute these in

138 = 2.15 (40)^2 / (64.4 *f)

simplify

138 = 2.15 (*1600) / (64.4 *f)

138 = 3440 / (64.4 *f)

multiply each side by 64.4f

138 * 64.4 f = 3440

8887.2 f = 3440

divide by 8887.2

8887.2 f /8887.2= 3440/8887.2

f=.38707

to the nearest hundredth

f = .39

8 0
3 years ago
Read 2 more answers
) The National Assessment of Educational Progress (NAEP) gave a test of basic arithmetic and the ability to apply it in everyday
Vsevolod [243]

Answer:

a) The standard deviation of this sampling distribution is 2.07.

b) The missing number is 4.14.

c) The 95% confidence interval for the population mean score μ based on this one sample is between 267.86 and 276.14.

Step-by-step explanation:

To solve this question, we need to understand the Empirical Rule and the Central Limit Theorem.

Empirical Rule:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

Central Limit Theorem:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question:

\mu = 272, n = 840, \sigma = 60

(a) If we take many samples, the sample mean x⎯⎯⎯ varies from sample to sample according to a Normal distribution with mean equal to the unknown mean score μ in the population. What is the standard deviation of this sampling distribution?

Using the Central Limit Theorem:

s = \frac{\sigma}{\sqrt{n}} = \frac{60}{\sqrt{840}} = 2.07

The standard deviation of this sampling distribution is 2.07.

(b) According to the 95 part of the 68-95-99.7 rule, 95% of all values of x⎯⎯⎯ fall within _______ on either side of the unknown mean μ. What is the missing number?

Within 2 standard deviations of the mean.

So, 2*2.07 = 4.14

The missing number is 4.14.

(c) What is the 95% confidence interval for the population mean score μ based on this one sample?

Within 4.14 of the mean

272 - 4.14 = 267.86

272 + 4.14 = 276.14

The 95% confidence interval for the population mean score μ based on this one sample is between 267.86 and 276.14.

6 0
3 years ago
Angles A and B are located in the first quadrant such that sinA= 7/25 and cosB = 5/13. Determine the exact value for cos (A-B).
fomenos

Answer:

  204/325

Step-by-step explanation:

You can work this a couple of ways. We expect you are probably expected to use trig identities.

  cos(A) = √(1 -sin²(A)) = 24/25

  sin(B) = √(1 -cos²(B)) = 12/13

cos(A -B) = cos(A)cos(B) +sin(A)sin(B) = (24/25)(5/13) +(7/25)(12/13)

  = (24·5 +7·12)/325

cos(A -B) = 204/325

__

The other way to work this is using inverse trig functions. It is necessary to carry the full calculator precision if you want an exact answer.

  cos(A -B) = cos(arcsin(7/25) -arccos(5/13)) = cos(16.2602° -67.3801°)

  = cos(-51.1199°) ≈ 0.62769230 . . . . (last 6 digits repeating)

The denominators of 25 and 13 suggest that the desired fraction will have a denominator of 25·13 = 325, so we can multiply this value by 325 to see what we get.

  325·cos(A-B) = 204

so, the exact value is ...

  cos(A -B) = 204/325

8 0
2 years ago
Carlos makes 1 pound of snack mix using nuts, raisins, and cereal. He uses 1/3 pound of nuts and 2/5 pound of raisins. How much
MArishka [77]
1 11/15 lbs of cereal
3 0
2 years ago
Read 2 more answers
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