Answer:
Probability that the measure of a segment is greater than 3 = 0.6
Step-by-step explanation:
From the given attachment,
AB ≅ BC, AC ≅ CD and AD = 12
Therefore, AC ≅ CD = 
= 6 units
Since AC ≅ CD
AB + BC ≅ CD
2(AB) = 6
AB = 3 units
Now we have measurements of the segments as,
AB = BC = 3 units
AC = CD = 6 units
AD = 12 units
Total number of segments = 5
Length of segments more than 3 = 3
Probability to pick a segment measuring greater than 3,
= 
= 
= 0.6
Answer:

Step-by-step explanation:
We start off with 3.2n + 13.3 = 26.1.
We need to get n by itself.
Subtract 13.3 from both sides.


We end up with: 
Divide 3.2 on both sides to get n by itself.

2x -1 is the answer I believe
The answer is: 10 x¹³ y¹⁰ .
__________________________________________________________
1x^8 * 2y^(10) * 5x^5 =
1* 2* 5 * x^8 * x^5 * y^(10) =
10 * x^(8+5) * y^(10) =
10 * x^(13) * y^(10) = 10 x^(13) y^10 ; write as:
_______________________________________________
10 x¹³ y¹<span>⁰ .
<span>______________________________________________________</span></span>