Given that,
KM bisects ∠LKJ.
m∠LKM = 4x + 12 and m∠MKJ = 6x - 6
To find,
The value of x.
Solution,
As KM bisects ∠LKJ. It would mean that,
m∠LKM = m∠MKJ
Putting the above values,
4x+12=6x-6
We can solve the above equations as follows :
4x-6x=-12-6
-2x=-18
x=9
Therefore, the value of x is equal to 9.
First, subtract 5 from both sides, leaving you with 5
- 30x - 5 = 0
If you use the quadratic formula (a=5), (b=-30), (c=-5)
x=-b +/- √b²-4ac / 2a
x= -(30) +/- √(30)² - 4(5) * (-5) / 2(5)
x= 30 +/- √1000 / 10
x = 3 +/- √10
Answer:
i beilive (a) is c idk i could be wrong..
Step-by-step explanation:
Answer:
C) x^2 + y^2 = 16
Step-by-step explanation:
<h2><u>Find the equation </u></h2>
since the radius is 4 this means that anywhere from the center of the circle to the edge of the circle is 4. hence :
place the horizontal line of the radius where y = 0 .
this means that if y = 0 , then x = 4
therefore :
x^2 + y^2
4^2 + 0^2
= 16
<h3><u>hence the answer is C ) x^2 + y^2 = 16</u></h3>
For this case, the first thing we must do is define variables:
x: unknown number (1)
y: unknown number (2)
We now write the equations that model the problem:
their sum is 6.1:
their difference is 1.6:
Solving the system we have:
We add both equations:
Then, we look for the value of y using any of the equations:
Answer:
The numbers are: