the highest batting average is of Ed's and that is 0.350 .
<u>Step-by-step explanation:</u>
Here we have , Make, Dan, Ed, and summer played together on a baseball team. Mike’s batting average was 0.349, dan’s was 0.2, Ed’s was 0.35, and sy’swas 0.299. We need to find Who had the highest batting average . Let's find out :
According to question we have following parameters as :

Arranging these data from decreasing to increasing order we get :
⇒ 
⇒ 
Therefore , the highest batting average is of Ed's and that is 0.350 .
50 as 10 multiplied by 50 equals 500
Answer:
Step-by-step explanation:
Let assume that Suppose the chance of contracting malaria is 10% for those who are not vaccinated ; (since the value) is not given.
Thus;
If the vaccine has no effect, risk of malaria for vaccine and no vaccine are equal to 0.1
Probability of not getting malaria if vaccinated or no vaccinated = 1 - 0.1 = 0.9
Malaria No Malaria Total
Vaccinated 100 * 0.1 = 10 100 * 0.9 = 90 100
No Vaccine 200 * 0.1 = 20 200 * 0.9 = 180 300-100 = 200
Total 20 + 10 = 30 90 + 180 = 270 300
If the vaccine cuts the risk by half, risk of malaria for vaccinated are equal to 0.1/2 = 0.05
Probability of not getting malaria if vaccinated = 1 - 0.05 = 0.95
Malaria No Malaria Total
Vaccinated 100 * 0.05 = 5 100 * 0.95 = 95 100
No Vaccine 200 * 0.1 = 20 200 * 0.9 = 180 300-100 = 200
Total 20 + 5 = 25 90 + 180 = 275 300
Complete question :
The average daily volume of a computer stock in 2011 was p = 35.1 million shares, according to a reliable source. A stock analyst believes that the stock volume in 2014 is different from the 2011 level. Based on a random sample of 40 trading days in 2014, he finds the sample mean to be 30.9 million shares, with a standard deviation of s = 11.8 million shares. Test the hypotheses by constructing a 95% confidence interval. Complete parts (a) through (c) below. State the hypotheses for the test. Construct a 95% confidence interval about the sample mean of stocks traded in 2014.
Answer:
H0 : μ = 35.1 ;
H1 : μ < 35.1 ;
(26.488 ; 35.312)
Step-by-step explanation:
The hypothesis :
H0 : μ = 35.1
H1 : μ < 35.1
The confidence interval :
Xbar ± Margin of error
Xbar = 30.9
Margin of Error = Zcritical * s/sqrt(n)
Zcritical at 95% = 1.96
Margin of Error = 1.96 * (11.8/sqrt(40))
Margin of Error = 4.412
Lower boundary :
30.9 - 4.412 = 26.488
Upper boundary :
30.9 + 4.412 = 35.312
Confidence interval = (26.488 ; 35.312)
Since the population mean value exists within the interval, the we fail to reject the Null.