Calculate the value of 5÷ 1+2 x 3

Bill is a used car salesman. He sells a used automobile for $15,799. If he receives a 4%

Scrat [10]

Answer: 4 cents or .4

Step-by-step explanation:

Whenever in a problem like this where there is a fee, tax, and or bonus you move the decimal in front of the number and round to the nearest penny but if there is only one number in front of the decimal you don’t gotta do anything with it unless its .5 or higher but .4 and below you keep the same.

7 0

2 years ago

19p-6(4p-8)=7(p-12)<br> Pls help am confused

elena-s [515]

Answer:

p=11

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Find all zeros<br>f(x)=x^4+6x^3+173x^2+332x+164

zheka24 [161]

The zeros are (-1,0)

6 0

3 years ago

The weight of an adult swan is normally distributed with a mean of 26 pounds and a standard deviation of 7.2 pounds. A farmer ra

Snezhnost [94]

Let $X$ denote the random variable for the weight of a swan. Then each swan in the sample of 36 selected by the farmer can be assigned a weight denoted by $X_1,\ldots,X_{36}$ , each independently and identically distributed with distribution $X_i\sim\mathcal N(26,7.2)$ .

You want to find

$\mathbb P(X_1+\cdots+X_{36}>1000)=\mathbb P\left(\displaystyle\sum_{i=1}^{36}X_i>1000\right)$

Note that the left side is 36 times the average of the weights of the swans in the sample, i.e. the probability above is equivalent to

$\mathbb P\left(36\displaystyle\sum_{i=1}^{36}\frac{X_i}{36}>1000\right)=\mathbb P\left(\overline X>\dfrac{1000}{36}\right)$

Recall that if $X\sim\mathcal N(\mu,\sigma)$ , then the sampling distribution $\overline X=\displaystyle\sum_{i=1}^n\frac{X_i}n\sim\mathcal N\left(\mu,\dfrac\sigma{\sqrt n}\right)$ with $n$ being the size of the sample.

Transforming to the standard normal distribution, you have

$Z=\dfrac{\overline X-\mu_{\overline X}}{\sigma_{\overline X}}=\sqrt n\dfrac{\overline X-\mu}{\sigma}$

so that in this case,

$Z=6\dfrac{\overline X-26}{7.2}$

and the probability is equivalent to

$\mathbb P\left(\overline X>\dfrac{1000}{36}\right)=\mathbb P\left(6\dfrac{\overline X-26}{7.2}>6\dfrac{\frac{1000}{36}-26}{7.2}\right)$
$=\mathbb P(Z>1.481)\approx0.0693$

5 0

2 years ago

1. Mark and Bill have a combined weight of 170

qwelly [4]

<h3>Equation : x + y = 170 and y = 2x - 40</h3><h3>The weight of Bill is 70 pounds and weight of mark is 100 pounds</h3>

<em><u>Solution:</u></em>

Let the weight of Bill be "x"

Let the weight of mark be "y"

Given that,

Mark and Bill have a combined weight of 170 pounds

Therefore,

x + y = 170 ------- eqn 1

Mark weighs 40 pounds less than twice Bill's weight

y = 2x - 40 ------- eqn 2

<em><u>Substitute eqn 2 in eqn 1</u></em>

x + 2x - 40 = 170

3x = 170 + 40

3x = 210

x = 70

<em><u>Substitute x = 70 in eqn 2</u></em>

y = 2(70) - 40

y = 140 - 40

y = 100

Thus weight of Bill is 70 pounds and weight of mark is 100 pounds

6 0

3 years ago

Calculate the value of 5÷ 1+2 x 3​

Calculate the value of 5÷ 1+2 x 3