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3 years ago

(02.02 MC)

Mathematics

2 answers:

Yuki888 [10]3 years ago

6 0

R'S' is equal in length to RS.

length doesnt change, it was just rotated.

-BARSIC- [3]3 years ago

5 0

I think it's R'S' is equal in length to RS.

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The radius of a right circular cylinder is increasing at a rate of 9 inches per minute and the height is decreasing at a rate of

pav-90 [236]

Answer:

$\frac{dA}{dt}=1840.97 in^{2}/min$

Step-by-step explanation:

The equation of the surface of the right circular cylinder is:

$A=2\pi rh+2\pi r^{2}=2\pi(rh+r^{2})$

Now, the rate change of this area will be:

Using the change rule

$\frac{dA}{dt}=\frac{\partial A}{\partial r}\frac{\partial r}{\partial t}+\frac{\partial A}{\partial h}\frac{\partial h}{\partial t}$

Where:

$\frac{\partial h}{\partial t}$ is the rate change of height (-16 in/min)
$\frac{\partial r}{\partial t}$ is the rate change of radius (9 in/min)

$\frac{dA}{dt}=\frac{\partial A}{\partial r}9+\frac{\partial A}{\partial h}(-16)$

$\frac{dA}{dt}=2\pi(h+2r)9-2\pi r16=2\pi((h+2r)9-16r)$

Now, r = 16 and h = 29

$\frac{dA}{dt}=2\pi((29+2*16)9-16*16)$

$\frac{dA}{dt}=1840.97 in^{2}/min$

I hope it helps you!

8 0

4 years ago

Factorise this expression:

Vesnalui [34]

Yes you are correct, GCF of both terms is x, so you can factor x out.

3x - x² ⇒ x(3 - x)

6 0

3 years ago

Read 2 more answers

a class is participating in a walkathon fundraiser each of the 22 students walk 52 laps around the track during the four hours o

KengaRu [80]

Hi! Your answer is 13.

All you have to do is divide 52 by 4. When you do this, you will find how many laps they walked per hour.

(They walked 52 laps in 4 hours)

52 / 4 = 13

They walked 13 laps in one hour.

Hope this helped!

6 0

4 years ago

PLEASE HELPPPPPPPPPPPP ME! THANK YOU!

Ainat [17]

Answer:

x=0

x=10

x=24

Step-by-step explanation:

f(x) = -.05x^2 + x +6

The initial value is 6 ( Let x=0 and f(0) = 6)

f(x) = -.05( x^2 -20 x -120)

I plotted the equation and maximum is at x=10 and the zero is at x=25

3 0

4 years ago

A manufacturer of banana chips would like to know whether its bag filling machine works correctly at the 447 gram setting. It is

lord [1]

Answer:

A manufacturer of banana chips would like to know whether its bag filling machine works correctly at the 447 gram setting.

$H_0:\mu = 447\\H_a:\mu\neq 447$

Mean = $\mu = 447\\s = 21\\x = 443$

n = 19

Since n < 30 , so we will use t test

$t=\frac{x-\mu}{\frac{s}{\sqrt{n}}}$

Substitute the values :

$t=\frac{443-447}{\frac{21}{\sqrt{19}}}$

$t=−0.8302$

t calculated = -0.830

degree of freedom = n-1 = 19-1 = 18

A level of significance=α=0.025

$t_{(df,\frac{\alpha}{2})}=2.093$

t critical = 2.093

t calculated < t critical

So, We failed to reject null hypothesis

Decision rule -0.830< 2.093 So, We failed to reject null hypothesis

4 0

3 years ago