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TEA [102]
3 years ago
8

the length of a rectangle is three times more than the length. the perimeter is 48in. what are the width and length of the trian

gle?
Mathematics
1 answer:
Natalka [10]3 years ago
8 0

Answer:

Length = 18 inches

Width = 6 inches

Step-by-step explanation:

The length (l) of a rectangle is three times more than the width (w).

The perimeter of the rectangle is 48 inches.

Let's say the width of this rectangle is x inches.

The length will be 3x inches.

Perimeter of a rectangle = 2l + 2w

So 2(3x) + 2x = 48 inches

6x + 2x = 48 inches

8x = 48 inches

x = 6 inches

So the width of the rectangle is 6 inches and the length is 3 × 6 = 18 inches

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On a coordinate plane, point A is 7 units to the left. Point B is at (0, 0). Point C is 7 units to the right. Point D is 7 units
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Which statute generates statistical data that is generally cited to support findings.
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5 0
2 years ago
In Illinois, 9% of all drivers arrested for DUI (Driving Under the Influence) are repeat offenders; that is, they have been arre
Veseljchak [2.6K]

Answer:

a) 21.58% probability that exactly 3 people are repeat offenders

b) 97.91% probability that at least one person is a repeat offender

c) 3.69

d) 1.83

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

9% of all drivers arrested for DUI (Driving Under the Influence) are repeat offenders

This means that p = 0.09

41 people arrested for DUI in Illinois are selected at random.

This means that n = 41

a. What is the probability that exactly 3 people are repeat offenders?

This is P(X = 3).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 3) = C_{41,3}.(0.09)^{3}.(0.91)^{38} = 0.2158

21.58% probability that exactly 3 people are repeat offenders

b. What is the probability that at least one person is a repeat offender?

Either none are repeat offenders, or at least one is. The sum of the probabilities of these outcomes is 1. So

P(X = 0) + P(X \geq 1) = 1

We want P(X \geq 1).

Then

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = 0) = C_{41,0}.(0.09)^{0}.(0.91)^{41} = 0.0209

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0209 = 0.9791

97.91% probability that at least one person is a repeat offender

c. What is the mean number of repeat offenders?

E(X) = np = 41*0.09 = 3.69

d. What is the standard deviation of the number of repeat offenders?

\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{41*0.09*0.91} = 1.83

4 0
3 years ago
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