Answer:
604800 possibilities
Step-by-step explanation:
There are two sets.
The first set is for the first five machining operations. This set has the following operations: A,B,C,D,E
The first operation to be made can be any of them(A,B,C,D,E). The second will be any of the four remaining ones, the third will be any of the three remaining and so on...
So for the first set there are 5*4*3*2*1 = 5! = 120 possibilities.
Now for the second set, the same logic is applied.
There will be 7*6*5*4*3*2*1 = 7! = 5040 possibilities.
Now taking into account all the 12 operations, separated by set, there will be 120*5040 = 604800 possibilities.
You can understand this calculus as that for a simple possibility of the first set, there are 5040 possibilities of the second set. The are 120 possiblities in the first set, so we have the multiplication in the paragraph above.
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, we factor out and divide by a 9 to get
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