Question

CAN SOMEONE HELP ME WITH THESE MATH QUESTIONS

Answer 1

1 B
2 C
3 D
4 A
5 B

Those are your answers

Answer 2

Answer:

1.

Let the length be = l

Let the width be = w

The length of a rectangle is three times its width. So, $l=3w$

If the perimeter is at most 112 centimeters, means it should exceed 112 cm.

We can define these as : $2l+2w \leq 112$

Substituting l = 3w

$2(3w)+2w \leq 112$ (option B)

2.

We have to solve the above equation here.

$2(3w)+2w \leq 112$

=> $6w+2w \leq112$

=> $8w \leq112$

=> $w \leq14$

So, width can be at most 14 cm.  (option C)

3.

Eduardo spent $7500 to obtain his merchandise, and it costs him $300 per week for general expenses.

He earns $850 per week in sales.

Let the number of weeks needed be = w

So, the inequality here becomes:

$850w>7500+300w$   (option B)

4.

Reiko spent $5200 to obtain her merchandise, and it costs her $550 per week for general expenses.

She earns $900 per week in sales.

Let the weeks be w

So, inequality here becomes;

$900w>5200+550w$

Solving this we get;

$900w-550w>5200$

$350w>5200$

$w>14.85$

So, the minimum number of weeks needed to get profit will be 15 weeks (option A)

5.

Let Jenny's age be J

Let Sue's age be S

Jenny is eight years older than twice her cousin Sue’s age.

So we get, $J=8+2S$   ....(1)

The sum of their ages is less than 32. We get $J+S$   ....(2)

Substituting J=8+2S in (2)

$8+2S+S$

$3S+8$

$3S$

$3S$

$S$

We get Sue's age =7 (option A)