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meriva
4 years ago
14

Find the solution to this system: A. (2,1) B. (1,-2) C. (1,2) D. (-1,2)<br />NEED HELP

Mathematics
1 answer:
Rasek [7]4 years ago
6 0
The solution to the system is where the lines intercept. If you look at the graph, you see that the lines intercept at (1,2). So, the answer would be C.
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A cylinder shaped water tank has a diameter of 8 m and a height of 20 m.
aev [14]

Answer:

602.88 cu ft.

Step-by-step explanation:

V = Bh where B is the area of the base, which is a circle in your problem.

Since the diameter is 8, the radius is 4.

So, B = \pi r^{2}  = 3.14(4^{2} )  = 3.14(16) = 50.24

V = Bh = 50.24(20) = 1004.8 cu ft = total volume of tank

60% of that volume is .60(1004.8) = 602.88 cu ft.

7 0
3 years ago
which of the following equations is modeled by the graph? a. a = 50t b. a = 5t c. a = 50 + t d. a = 10t
lubasha [3.4K]

Answer:

c

Step-by-step explanation:

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3 years ago
in an over-fished area, the catch of a certain type of fish is decreasing at an average rate of 8% per year. If this decline per
Galina-37 [17]
<span>n = n0(1 - 0.08)^t 
= n0(0.92)^t 

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4 0
3 years ago
Using the equation y−1=2(x+3) , find a point that is on the line when graphed.
VLD [36.1K]

Answer:

(- 3, 1 )

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

y - 1 = 2(x + 3) ← is in point- slope form

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7 0
4 years ago
Suppose F and G are continuously∗ differentiable functions defined on [a, b] such that F0(x) = G0(x) for all x ∈ [a, b]. Using t
Orlov [11]

Answer:

The proof is detailed below.

Step-by-step explanation:

We will first prove that if H(x) is a differentiable function in [a,b] such that H'(x)=0 for all x∈[a, b] then H is constant. For this, take, x,y∈[a, b] with x<y. By the Mean Value Theorem, there exists some c∈(x,y) such that H(y)-H(x)=H'(c)(x-y). But H'(c)=0, thus H(y)-H(x)=0, that is, H(x)=H(y). Then H is a constant function, as it takes the same value in any two different points x,y.

Now for this exercise, consider H(x)=F(x)-G(x). Using differentiation rules, we have that H'(x)=(F-G)(x)'=F'(x)-G'(x)=0. Applying the previous result, F-G is a constant function, that is, there exists some constant C such that (F-G)(x)=C.

3 0
4 years ago
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