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4 years ago

Multiply and reduce to lowest terms. Convert into a mixed number if necessary. 4x5/9=

Mathematics

1 answer:

QveST [7]4 years ago

4 0

2 and 1/5 is your answer.

decimal form=2.2

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Clarence measures the diameter of each tennis ball and a bag with a standard ruler. Unfortunately he uses the ruler and correctl

ollegr [7]

Refer to the figure below.

Assume that there are n correct measurements
$x_{i} , \, i=1,2, \, ... \, n$
Because each measurement has an error of 0.2 in, the actual measurements are
$x_{i} + 2$

From the figure, the analysis indicates that the correct mean is
μ = 3 in = 3*2.54 cm = 7.62 cm
The correct standard deviation is
2.934 in = 2.934*2.54 cm = 7.45 cm

Answer:
μ = 7.62 cm
σ = 7.45 cm

7 0

3 years ago

Assume a student shows up for EGR 280 completely unprepared and the instructor gives a pop quiz. Assume there are 6 questions, e

Kisachek [45]

Answer:

P=20%

Step-by-step explanation:

Let's suppose that each question in the test has one and only one correct answer. This means we have 1 desired outcome out of the total 5 desired outcomes. Therefore:

Probability=#of desired outcomes / #of possible outcomes

$P=\frac{1 correct}{5 opctions}$

$P=\frac{1}{5}$

P=0.20

P=20%

7 0

3 years ago

How can I express this as a single power with positive exponents?

Tamiku [17]

Answer:

5^1

Step-by-step explanation:

$\sqrt{5} =5^{\frac{1}{2} }$ (law of indices - fractional powers)

after converting all the numbers to this form:

$\frac{5^{{\frac{2}{3} } } * 5^{\frac{1}{2} } }{5^{\frac{1}{6} } } \\$

combine using law of indices:

5^(2/3+1/2-1/6) = 5^1

3 0

3 years ago

SIX LESS THAN TWICE A NUMBER, X, IS 38 WHAT IS THE VALUE OF X

stealth61 [152]

Answer:

Step-by-step explanation:

first write the equation:

twice a number x is 2x

six less is -6

so equation is 2x - 6 = 38

solve for x:

2x = 34

x = 17

6 0

3 years ago

Read 2 more answers

Suppose that the functions p and q are defined as follows.

Brut [27]

<h2>Answer:</h2>

Answer:

(r o q)(-1) = 20

(q o r)(-1) = -11

Step-by-step explanation:

Given

q(x) = -2x + 1q(x)=−2x+1

r(x) = 2x^2 + 2r(x)=2x2+2

Solving (a): (r o q)(-1)

In function:

(r o q)(x) = r(q(x))

So, first we calculate q(-1)

q(x) = -2x + 1q(x)=−2x+1

q(-1) = -2(-1) + 1q(−1)=−2(−1)+1

q(-1) = 2 + 1q(−1)=2+1

q(-1) = 3q(−1)=3

Next, we calculate r(q(-1))

Substitute 3 for q(-1)in r(q(-1))

r(q(-1)) = r(3)

This gives:

r(x) = 2x^2 + 2r(x)=2x2+2

r(3) = 2(3)^2 + 2r(3)=2(3)2+2

r(-1) = 2*9 + 2r(−1)=2∗9+2

r(-1) = 20r(−1)=20

Hence:

(r o q)(-1) = 20

Solving (b): (q o r)(-1)

So, first we calculate r(-1)

r(x) = 2x^2 + 2r(x)=2x2+2

r(-1) = 2(-1)^2 + 2r(−1)=2(−1)2+2

r(-1) = 2*1 + 2r(−1)=2∗1+2

\begin{gathered}r(-1) = 6\\\end{gathered}r(−1)=6

Next, we calculate r(q(-1))

Substitute 6 for r(-1)in q(r(-1))

q(r(-1)) = q(6)

q(x) = -2x + 1q(x)=−2x+1

q(6) = -2(6) + 1q(6)=−2(6)+1

q(6) =- 12 + 1q(6)=−12+1

q(6) = -11q(6)=−11

Hence:

(q o r)(-1) = -11

8 0

3 years ago