0=$5
1=$7
2=$9
3=$11
4=$13
5=$15
6=$17
Answer:
a) there is s such that <u>r>s</u> and s is <u>positive</u>
b) For any <u>r>0</u> , <u>there exists s>0</u> such that s<r
Step-by-step explanation:
a) We are given a positive real number r. We need to wite that there is a positive real number that is smaller. Call that number s. Then r>s (this is equivalent to s<r, s is smaller than r) and s is positive (or s>0 if you prefer). We fill in the blanks using the bold words.
b) The last part claims that s<r, that is, s is smaller than r. We know that this must happen for all posirive real numbers r, that is, for any r>0, there is some positive s such that s<r. In other words, there exists s>0 such that s<r.
Okay so.
If lawn tickets are $30 and seat tickets are $50 and they sold 200 seat tickets.
50 multiplied by 200 is = $ 10,000
And the goal is $14,000.
So $14,000 subtract $10,000 is $4000
$4000 is how much they made in Lawn Tickets. In order to calculate how much lawn tickets were sold, is dividing $4000 by $30 since lawn tickets are $30.
4000 divided by $30 = 133
Not sure if this is correct but all the working and steps are correct! Hope this helps.
Answer:

Step-by-step explanation:
<u>Ratios
</u>
We are given the following relations:
![a=\sqrt{7}+\sqrt{c}\qquad \qquad[1]](https://tex.z-dn.net/?f=a%3D%5Csqrt%7B7%7D%2B%5Csqrt%7Bc%7D%5Cqquad%20%5Cqquad%5B1%5D)
![b=\sqrt{63}+\sqrt{d}\qquad \qquad[2]](https://tex.z-dn.net/?f=b%3D%5Csqrt%7B63%7D%2B%5Csqrt%7Bd%7D%5Cqquad%20%5Cqquad%5B2%5D)
![\displaystyle \frac{c}{d}=\frac{1}{9} \qquad \qquad [3]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7Bc%7D%7Bd%7D%3D%5Cfrac%7B1%7D%7B9%7D%20%5Cqquad%20%5Cqquad%20%5B3%5D)
From [3]:

Replacing into [2]:

We can express 63=9*7:

Taking the square root of 9:

Factoring:

Find the ration a:b:

Simplifying:
