Question

In peas, tall plants (T) are completely dominant over short plants (t). You cross two heterozygous pea plants Use a Punnett square to determine the expected genotypic and phenotypic ratios of the offspring.What is the male pea plant's genotype?What is the female pea plant's genotype?What are the male pea plant's gametes?What are the female pea plant's gametes?What is the expected genotypic ratio of the offspring?What is the expected phenotypic ratio of the offspring?

Answer 1

Answers and Explanation:

Find enclosed the Punnet square.

T= dominant allele

t= recessive allele

Tt= heterozygous genotype

TT and tt= homozygous genotype

- The male pea plant's genotype is Tt (heterozygous)

- The female pea plant's genotype is Tt (heterozygous)

- Male gametes: T and t

- Female gametes: T and t

- The expected genotypic ratio of the offpring will be:

TT: Tt: tt ⇒ 1: 2: 1

1/4 of the offpring will be TT genotype (dominant homozygous), 1/2 of the offpring will be Tt (heterozygous) genotype and 1/4 of the offpring will be tt genotype (recessive homozygous).

- The expected phenotypic ratio of the offpring will be:

tall : short ⇒ 3 : 1

3/4 of the offpring will be tall (TT and Tt) and the restant 1/4 will be short (tt).