$i^7 + \dfrac 1{i^4}\\\\=i^2 \cdot i^2 \cdot i^2 \cdot i + \dfrac 1{i^2 \cdot i^2}\\\\=(-1)(-1)(-1)i + \dfrac 1{(-1)(-1)} ~~~;[ i^2 = -1] \\\\\ = (-1)^3 i+ \dfrac 1{(-1)^2} \\\\=-i+1$

7 0

2 years ago

Does anybody know this?

Ugo [173]

The coordinates of C are (a+c, b)
Coordinates of midpoint of AC are (a+c/2, b/2)

Coordinates of BD are (a+c/2, b/2)

6 0

2 years ago

Are these ratios equivalent?

zhenek [66]

No because 5/2= 2,5 however 63/19=3,66...

7 0

2 years ago