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Mrac [35]
3 years ago
13

In the first set the volleyball team made only 8 shots worth one point each write a algebraic expression

Mathematics
2 answers:
Elina [12.6K]3 years ago
4 0

Answer:

The required algebraic expression for given situation is 8×1.

Step-by-step explanation:

It is given that in the first set the volleyball team made only 8 shots worth one point each.

Total number of shots = 8

Point on each shot = 1

Total points = Total number of shots × Point on each shot

Total points = 8×1

Total points = 8

Therefore the required algebraic expression for given situation is 8×1 and the total score is 8.

icang [17]3 years ago
3 0
1 times 8  is your answer
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Advocard [28]

Answer:

20 feet

Step-by-step explanation:

There are 3 feet in a yard, so 9 yards and 1 foot = 28 feet. You find this by multiplying 9x3 = 27 and adding the extra foot, which makes it 28. To find the final answer just subtract 8 from 28, which gives you 20.

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How much percentage of a minute is a second?
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Which sequences of transformations confirm the congruence of shape II and shape I?
mylen [45]

Answer:

1. When we reflect the shape I along X axis it will take the shape I in first quadrant, and then if we rotate the shape I by 90° clockwise, it will take the shape again in second quadrant . So we are not getting shape II. This Option is Incorrect.

2. Second Option is correct , because by reflecting the shape I across  X axis and then by 90° counterclockwise rotation will take the Shape I in second quadrant ,where we are getting shape II.

3. a reflection of shape I across the y-axis followed by a 90° counterclockwise rotation about the origin takes the shape I in fourth Quadrant. →→ Incorrect option.

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6 0
2 years ago
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Could someone help me and explain?
ExtremeBDS [4]

Answer:

  • length 3 in
  • width 2 in

Step-by-step explanation:

Since none of the answer choices match the drawing of the gardener, we assume the question is referring to the drawing of the partner.

The gardener's drawing is 1/4 of actual size. So, in terms of the gardener's drawing, actual size is ...

  gardener's drawing = (1/4)actual size

  actual size = 4(gardener's drawing)

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The partner's drawing is 1/20 of actual size, so is ...

  partner's drawing = actual size/20 = (4(gardener's drawing))/20

  partner's drawing = (4/20)(gardener's drawing)

  partner's drawing = (gardener's drawing)/5

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Then the {length, width} of the partner's drawing are ...

  partner's drawing {length, width} = {15 in, 10 in}/5 = {3 in, 2 in}

The partner's drawing has a length of 3 inches and a width of 2 inches.

6 0
3 years ago
If , find the value of 2 square root of 17-x = 2x-10, find the value of x/4.
ira [324]
2 \sqrt{17-x} =2x-10\ \ \ \ \Rightarrow\ \ \ D:(17-x \geq 0\ \ \ and\ \ \ 2x-10 \geq 0)\\.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x \leq 17\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  \ \ x \geq 5\\\\.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ D=\\\\2 \sqrt{17-x} =2(x-5)\ /:2\\\\ \sqrt{17-x} =x-5\ \ \ \Rightarrow\ \ \ (\sqrt{17-x})^2 =(x-5)^2\\\\17-x=x^2-10x+25\\\\

x^2-9x+18=0\\\\ x^2-3x-6x+18=0\\\\x(x-3)-6(x-3)=0\\\\(x-3)(x-6)=0\ \ \ \ \Leftrightarrow\ \ \ (x-3=0\ \ \ \ or\ \ \ \ x-6=0)\\\\x=3\ \notin\ D\ \ \ \ \ \ \ \ \ \ \ x=6\ \in\ D\ \ \ \Rightarrow\ \ \  \frac{x}{4} = \frac{6}{4} =1.5\\\\Ans.\  \frac{x}{4} =1.5
7 0
3 years ago
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