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2 years ago

If f(x) = 2 + 1, then f(3) =

Mathematics

2 answers:

Andrei [34K]2 years ago

4 0

Answer:

Search it up then you will get the answer

Step-by-step explanation:

Luda [366]2 years ago

3 0

Answer:

D.9

Step-by-step explanation:

Plug in 3 for x.

2^3=8

8+1=9

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I need the ordered pair plz

Taya2010 [7]

Answer:

$(\frac{-1}{2},-1)$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Midpoint Formula: $(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

Step-by-step explanation:

Step 1: Define

Find points from graph.

Point (-6, 5)

Point (5, -7)

Step 2: Find Midpoint

Simply plug in your coordinates into the midpoint formula to find midpoint

Substitute [MF]: $(\frac{-6+5}{2},\frac{5-7}{2})$
Add/Subtract: $(\frac{-1}{2},\frac{-2}{2})$
Divide: $(\frac{-1}{2},-1)$

4 0

2 years ago

The graph of y = x2 - 4x is shown on the grid.

MArishka [77]

Answer:

i dont know it (sad face)

Step-by-step explanation:

3 0

2 years ago

Write the expression using rational exponents. Then simplify and convert back to radical notation.

ioda

Answer:

The radical notation is $3x\sqrt[3]{y^2z}$

Step-by-step explanation:

Given

$\sqrt[3]{27 x^{3} y^{2} z}$

Step 1 of 1

Write the expression using rational exponents.

$\sqrt[n]{a^{m}}=\left(a^{m}\right)^{\frac{1}{n}}$

$=a^{\frac{m}{n}}:\left({27 x^{3} y^{2} z})^{\frac{1}{3}}$

$(a \cdot b)^{r}=a^{r} \cdot b^{r}:(27)^{\frac{1}{3}}\left(x^{3}\right)^{\frac{1}{3}} \cdot\left(y^{2}\right)^{\frac{1}{3}} \cdot(z)^{\frac{1}{3}}$

$=$(3^3)^{\frac{1}{3}}\left(x^{3}\right)^{\frac{1}{3}} \cdot\left(y^{2}\right)^{\frac{1}{3}} \cdot(z)^{\frac{1}{3}}$$

$=\left(3\right)\left(x}\right)} \cdot\left(y}\right)^{\frac{2}{3}} \cdot(z)^{\frac{1}{3}}$

$=3x \cdot(y)^{\frac{2}{3}} \cdot(z)^{\frac{1}{3}}$

Simplify $3 x \cdot(y)^{\frac{2}{3}} \cdot(z)^{\frac{1}{3}}$

$=3 x \sqrt[3]{y^{2} z}$

Learn more about radical notation, refer :

brainly.com/question/15678734

4 0

2 years ago

On $500 at 6% for 18 months what is the interest

blsea [12.9K]

It would be $45. The equation is 500×0. 06×1.5

6 0

3 years ago

Given isosceles ABC, median BD to base AC. Prove ADB=CDB. AB=, AD=, BD=, ADB=

lesya692 [45]

Answer:

1. AB=CB def of isosceles triangle

2. AD=CD DEF of median

3. BD=DB reflexive property

4. ADB=CDB SSS

Step-by-step explanation:

ummmm its just the right answer trust

5 0

2 years ago