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babymother [125]
3 years ago
13

Question 9. True or false? Provide a simple counter-example if it is false. (9.a) The sum of two rational numbers x, y EQ is alw

ays a rational number, x+y EQ. (9.b) The sum of two irrational numbers x, y ER - Q is always an irrational number, x +y ER-Q. (9.c) The sum of the squares of two distinct real numbers x,y ER, with x #y, is always a positive real number, x2 + y2 ER and x2 + y2 > 0. (9.d) If a, b ER, then ab E R.
Mathematics
1 answer:
eimsori [14]3 years ago
8 0

Answer:

a. True. Rational numbers are closed under the sum operation, therefore, the sum of two rational numbers is always a rational number.

b. True. irrational numbers are closed under the sum operation, therefore, the sum of two irrationals numbers is always a irrational number.

c. True. The square of a real number is always a number greater than zero, and the sum of two numbers greater than zero is greater than zero.

d. True. The real numbers are closed under the product operation, then if a and b are reals numbers, the product ab is also a real number.

Step-by-step explanation:

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Answer:

x = 5

Step-by-step explanation:

<u>__________________________________________________________</u>

<u>FACTS TO KNOW BEFORE SOLVING</u> :-

  • a^x \times a^y = a^{x+y}
  • In an equation , if the bases are same in both L.H.S. & R.H.S. then , the power of the bases on both the sides of equation should be equal. For e.g. : a^x = a^y  ⇒  x = y  [∵ Bases are equal on both the sides]

<u>__________________________________________________________</u>

4 \times 8^{2x+1} = 32^{x+2}

Lets express it in terms of 2.

=> 2^2 \times 2^{3 (2x+1)} = 2^{5(x+2)}

=> 2^2 \times 2^{6x+3} = 2^{5x+10}

=> 2^{2 + 6x+3} = 2^{5x+10}

=> 2^{6x+5} = 2^{5x+10}

Here the bases on both the sides are equal. Hence ,

=> 6x + 5 = 5x + 10

=> 6x - 5x = 10 - 5

=> x = 5

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