Answer:
-4
Step-by-step explanation:
I used my smarts
Step-by-step explanation:
z
3
=8(cos216
∘
+isin216
∘
)
z^3=2^3(\cos(6^3)^\circ+i\sin(6^3)^\circ)z
3
=2
3
(cos(6
3
)
∘
+isin(6
3
)
∘
)
\implies z=8^{1/3}\left(\cos\left(\dfrac{216+360k}3\right)^\circ+i\sin\left(\dfrac{216+360k}3\right)^\circ\right)⟹z=8
1/3
(cos(
3
216+360k
)
∘
+isin(
3
216+360k
)
∘
)
where k=0,1,2k=0,1,2 . So the third roots are
\begin{gathered}z=\begin{cases}2(\cos72^\circ+i\sin72^\circ)\\2(\cos192^\circ+i\sin192^\circ)\\2(\cos312^\circ+i\sin312^\circ)\end{cases}\end{gathered}
z=
⎩
⎪
⎪
⎨
⎪
⎪
⎧
2(cos72
∘
+isin72
∘
)
2(cos192
∘
+isin192
∘
)
2(cos312
∘
+isin312
∘
)
Can you show me the drop down menus so I could help you
The answer to your problem would be -8
I got this because if you take 4 - 2x to the third power, it would look like this:
(4 - 2x)^3
All you have to do it plug in 3, solve for the equation in the parentheses, and then take that number to the third power. In this case, you get -2, and if you take that to the third power, you get -8.
Hope this helps!
3/8 0.37><span>7/10 0.073 hope I helped</span>
