All categories

3 years ago

Hey!I'm a student.Can you help me solve this question?Thanks!

Mathematics

2 answers:

inysia [295]3 years ago

8 0

Answer:

Step-by-step explanation:

Just dont even try with these use a calculator every time. even if you're confident

Lilit [14]3 years ago

6 0

Answer:

Step-by-step explanation:

1+2 is the first equation to do, which equals 3. Then from the beginning we have 6 ÷2 and as there is no sign from this to the brackets it will be multiply. 6÷2 is 3. multiply it by 3 (what the brackets equal) and the answer is 9

You might be interested in

Find the distance between the points given. (-3, -4) and (0, 0)

nata0808 [166]

Distance between -4 and -3 is 1 and there is no distance between 0

7 0

3 years ago

Read 2 more answers

Which of the following represents the factorization of the binomial below ? X2-121

nataly862011 [7]

Answer:

(x+11)(x-11)

Step-by-step explanation:

A ^2 - B ^2 =(A+B) (A-B).. (*)

x^2 - 121=

x^2 - 11^2=(*)

(x+11)(x-11)

4 0

3 years ago

Read 2 more answers

If x is a positive integer and y is a negative integer than x + y is a rational number.

romanna [79]

Answer:

Yes

Step-by-step explanation:

An integer is a whole number so if x is positive and y is negative then the equation would just be x plus negative y. But x+-y is an odd equation so the simplified version is x-y so it is a rational number, since a rational number is a number that can be rewritten as a simple fraction.

5 0

3 years ago

Select the two values of x that are roots of this equation.<br> 2x^2+ 1 = 5x

iren [92.7K]

Answer:

$\frac{5+\sqrt{17}}{4}$ , $\frac{5-\sqrt{17}}{4}$

Step-by-step explanation:

One is asked to find the root of the following equation:

$2x^2+1=5x$

Manipulate the equation such that it conforms to the standard form of a quadratic equation. The standard quadratic equation in the general format is as follows:

$ax^2+bx+c=0$

Change the given equation using inverse operations,

$2x^2+1=5x$

$2x^2-5x+1=0$

The quadratic formula is a method that can be used to find the roots of a quadratic equation. Graphically speaking, the roots of a quadratic equation are where the graph of the quadratic equation intersects the x-axis. The quadratic formula uses the coefficients of the terms in the quadratic equation to find the values at which the graph of the equation intersects the x-axis. The quadratic formula, in the general format, is as follows:

$\frac{-b(+-)\sqrt{b^2-4ac}}{2a}$

Please note that the terms used in the general equation of the quadratic formula correspond to the coefficients of the terms in the general format of the quadratic equation. Substitute the coefficients of the terms in the given problem into the quadratic formula,

$\frac{-b(+-)\sqrt{b^2-4ac}}{2a}$

$\frac{-(-5)(+-)\sqrt{(-5)^2-4(2)(1)}}{2(2)}$