Answer:
If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is is dA/dt = 15 - 0.005A
Option C) dA/dt = 15 - 0.005A is the correction Answer
Step-by-step explanation:
Given the data in the question;
If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is?
dA/dt = rate in - rate out
first we determine the rate in and rate out;
rate in = 3pound/gallon × 5gallons/min = 15 pound/min
rate out = A pounds/1000gallons × 5gallons/min = 5Ag/1000pounds/min
= 0.005A pounds/min
so we substitute
dA/dt = rate in - rate out
dA/dt = 15 - 0.005A
Therefore, If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is is dA/dt = 15 - 0.005A
Option C) dA/dt = 15 - 0.005A is the correction Answer
The formula to calculate work done is -
Work done ( in joule, J) = Force (in Newton) X Distance (in meters)
So, we will use the formula to calculate work done,
Here, force is given as = 7 newtons
Distance is given as = 3 meters
So, work done will be -
Work done ( in joule, J) = 7 Newtons X 3 Meters
<u>Work done ( in joule, J) = 21 J (in joule)</u>
9514 1404 393
Answer:
72°
Step-by-step explanation:
The external angle E is half the difference of subtended arcs CG and DF.
E = (CG -DF)/2
2E = CG -DF . . . . . . multiply by 2
DF = CG -2E = 160° -2(44°) . . . . . add DF-2E to both sides; substitute values
arc DF = 72°