Answer:
The median weight for shelter A is greater than that for shelter B.
The data for shelter B are a symmetric data set.
The interquartile range of shelter A is greater than the interquartile range of shelter B.
Not sure but try 54 degrees
F(x) < 0 on the interval x < 0.
f(x) < 0 on the interval 0 < x < 1
f(x) > 0 on the interval 1 < x < 3
f(x) < 0 on the interval x > 3
Hello :
<span>f(x) = (x – 1)(x + 6)
f(x) =0
</span>(x – 1)(x + 6) = 0
x-1=0 or x+6=0
x=1 or x= -6.....(answers : B and D)
It is 33- 24 which is 9 ...