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3 years ago

Which is the measure of ∠XYZ?

Mathematics

1 answer:

AlladinOne [14]3 years ago

7 0

Answer:

you get the measure of angle XYZ by adding the measures of angles XY? and ZY?

70 +35 = 105 degrees is the measure of angle XYZ

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In a lottery game, a player picks six numbers from 1 to 27. If the player matches all six numbers, they win 40,000 dollars. Othe

Alexus [3.1K]

Answer:

We conclude that expected value of this game is -0.865$.

Step-by-step explanation:

We know that in a lottery game, a player picks six numbers from 1 to 27.

We know that

$C_6^{27}=296010$

As there is only one advantageous combination, we conclude that the number of non-winning combinations is 296009.

He can win 40,000 dollars.

We calculate:

$E(X)=\frac{1}{296010}\cdot 40000\$- \frac{296009}{296010}\cdot 1\$\\\\E(X)=\frac{40000-296009}{296010}\, \$\\\\E(X)=-0.865\, \$$

We conclude that expected value of this game is -0.865$.

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3 years ago

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denis23 [38]

Answer:

Step-by-step explanation:

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3 years ago

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KATRIN_1 [288]

3 is 23 degree
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3 years ago

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Suppose that X has a Poisson distribution with a mean of 64. Approximate the following probabilities. Round the answers to 4 dec

o-na [289]

Answer:

(a) The probability of the event (X > 84) is 0.007.

(b) The probability of the event (X < 64) is 0.483.

Step-by-step explanation:

The random variable X follows a Poisson distribution with parameter λ = 64.

The probability mass function of a Poisson distribution is:

$P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!};\ x=0, 1, 2, ...$

(a)

Compute the probability of the event (X > 84) as follows:

P (X > 84) = 1 - P (X ≤ 84)

$=1-\sum _{x=0}^{x=84}\frac{e^{-64}(64)^{x}}{x!}\\=1-[e^{-64}\sum _{x=0}^{x=84}\frac{(64)^{x}}{x!}]\\=1-[e^{-64}[\frac{(64)^{0}}{0!}+\frac{(64)^{1}}{1!}+\frac{(64)^{2}}{2!}+...+\frac{(64)^{84}}{84!}]]\\=1-0.99308\\=0.00692\\\approx0.007$

Thus, the probability of the event (X > 84) is 0.007.

(b)

Compute the probability of the event (X < 64) as follows:

P (X < 64) = P (X = 0) + P (X = 1) + P (X = 2) + ... + P (X = 63)

$=\sum _{x=0}^{x=63}\frac{e^{-64}(64)^{x}}{x!}\\=e^{-64}\sum _{x=0}^{x=63}\frac{(64)^{x}}{x!}\\=e^{-64}[\frac{(64)^{0}}{0!}+\frac{(64)^{1}}{1!}+\frac{(64)^{2}}{2!}+...+\frac{(64)^{63}}{63!}]\\=0.48338\\\approx0.483$

Thus, the probability of the event (X < 64) is 0.483.

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3 years ago

marking serious answers brainliest. The figure shown is a square with a triangular hole cut into one side. The ratio of the heig

NemiM [27]

Answer:

77.5

Step-by-step explanation:

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