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3 years ago

5. A cylinder has a diameter of 20 inches and a height of 9 inches

Mathematics

1 answer:

bulgar [2K]3 years ago

6 0

Answer:

The answer is about 2827.4 in cubed.

Step-by-step explanation:

The formula for the volume of a cylinder is

V = π·r²·h

Filling in the given information, your cylinder's volume is

V = π·(10 in)²·(9 in)

V = 900π in³

V ≈ 2827.4 in³

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VashaNatasha [74]

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a triangular sail has sides of 10 ft ,24ft,and 26ft .if the shortest side of a similar sail measures 6ft , what is the measure o

Katarina [22]

Answer:

15.6 ft

Step-by-step explanation:

Since the sails are similar then the ratios of corresponding sides are equal.

Comparing the shortest sides, that is

10 : 6 = 5 : 3

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4 years ago

A rectangle's width is 5 feet less than its length. If the area of the rectangle is 546 square feet, what is its length, in feet

Kitty [74]

W = L - 5

546 = L × ( L - 5 )
546 = L^2 - 5L
L^2 - 5L - 546 = 0
( L - 26 ) ( L + 21 ) = 0
L = 26 , L = - 21
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3 years ago

a local businesses bought a square ploy of land. the sides of the lot measure 32 feet on each side. he decides to split the lot

san4es73 [151]

Answer:

Approximate length of the diagonal fencing needed is 45.25 cm.

Step-by-step explanation:

Here, each side of the square shaped land = 32 ft

Now, the diagonal fencing is made in side the plot so that the land is divided into two right triangles.

In the triangle:

Base side of the triangle = 32 cm

Perpendicular length of the triangle = 32 cm

Let us assume the hypotenuse of the triangle = k cm

⇒The length of the diagonal in the square = k cm

by PYTHAGORAS THEOREM in a right angled triangle:

$(Base)^{2} + (Perpendicular)^{2} = (Hypotenuse)^{2}$

⇒ $(32)^2 + (32)^2 =k^2\\or, k^2 = 1024 + 1024 = 2048\\\implies k = \sqrt{2048} = 45.25$

or, k = 45.25 cm

Hence,the approximate length of the diagonal fencing needed to fence the square land is 45.25 cm.

6 0

3 years ago