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kvasek [131]
2 years ago
14

The average height of 5 students is 1.45 m. If one student left the group,the average height of the remaining four of them is 1.

44 m. What was the height of the student who left
Mathematics
1 answer:
SashulF [63]2 years ago
3 0

Answer:

4 students

Step-by-step explanation:

The average = sum of all observations divided by a number of observations. Sum of heights of 4 students = 1.44 ×4 = 5.76. Clearly, height of student who left = Sum of all heights - Sum of heights of 4 students.

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Answer:

                 x=8\frac34\ \,,\quad y=8\frac12

Step-by-step explanation:

             \Delta TRS\sim \Delta LJK \quad\implies\quad \dfrac{|TR|}{|LJ|}=\dfrac{|RS|}{|JK|}=\dfrac{|ST|}{|KL|}\\\\\dfrac{4}{7}=\dfrac{5}{x}=\dfrac{6}{y+2}\\\\\\\dfrac{4}{7}=\dfrac{5}{x}\quad\implies\quad4x=5\cdot7\quad\implies\quad x=\dfrac{35}4=8\frac34\\\\\\\dfrac{5}{x}=\dfrac{6}{y+2}\quad\implies\quad 5(y+2)=6\cdot\dfrac{35}4\\\\5y+10=3\cdot\dfrac{35}2\\\\5y\ =\ \dfrac{3\cdot35}2-10\\ \div5\qquad\quad \div5\\\\y=\dfrac{3\cdot7}2-2=10\frac12-2=8\frac12

3 0
4 years ago
Which of the following best describes the relationship between (x-2) and the polynomial 2x^3+x^2-3
pantera1 [17]
If (x - 2) is a factor of 2x³ + x² - 3 then for the value of x = 2 the polynominal is equal zero.
Substitute:
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Step-by-step explanation:


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4 years ago
Read 2 more answers
15. Construct the slope-intercept form equation of the line passing through (-5,23) and (10,-5).
Radda [10]

Answer:

15<em>y</em> = -28 <em>x</em> + 205.

Step-by-step explanation:

Slope intercept  form of equation is <em>y = mx + c</em> where m is slope and c is the y intercept.

Now slope of line passing through points (-5, 23) and (10, -5):

m = \frac{y_{2} - y_{1} }{x_{2} - x_{1} } = \frac{-5 -23}{10 + 5} = \frac{-28}{15}

Now equation of line:

<em> y = mx + c</em>

substituting the value of m in above expression,

y = -\frac{28}{15} x + c

Now, since the line is passing through the point (-5, 23) therefore, x = -5 and y = 23. By substituting these values in above equation,

23 = -\frac{28}{15} \times (-5) + c

23 = \frac{28}{3} + c

c = 23 - \frac{28}{3} = \frac{69 - 28}{3} = \frac{41}{3}

So equation of line in slope intercept form:

y = -\frac{28}{15} x + \frac{41}{3}

Further solving,

15<em>y</em> = -28 <em>x</em> + 205.

3 0
3 years ago
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