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kvasek [131]
2 years ago
14

The average height of 5 students is 1.45 m. If one student left the group,the average height of the remaining four of them is 1.

44 m. What was the height of the student who left
Mathematics
1 answer:
SashulF [63]2 years ago
3 0

Answer:

4 students

Step-by-step explanation:

The average = sum of all observations divided by a number of observations. Sum of heights of 4 students = 1.44 ×4 = 5.76. Clearly, height of student who left = Sum of all heights - Sum of heights of 4 students.

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Simplify and then classify by degree and number of terms<br> 2x+3x^2(4x-5)
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2x + 3x^2 (4x - 5)

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5 0
3 years ago
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In a G.P the 3rd term is 4 times the 1st term and the sum of the 2nd term and the 4th term is 30.find the common ratio,find the
STALIN [3.7K]

Answer:

the common ratio is either 2 or -2.

the sum of the first 7 terms is then either 765 or 255

Step-by-step explanation:

a geometric sequence or series of progression (these are the most common names for the same thing) means that every new term of the sequence is created by multiplying the previous term by a constant factor which is called the common ratio.

so,

a1

a2 = a1×f

a3 = a2×f = a1×f²

a4 = a3×f = a1×f³

the problem description here tells us

a3 = 4×a1

and from above we know a3 = a1×f².

so, f² = 4

and therefore the common ratio = f = 2 or -2 (we need to keep that in mind).

again, the problem description tells us

a2 + a4 = 30

a1×f + a1×f³ = 30

for f = 2

a1×2 + a1×2³ = 30

2a1 + 8a1 = 30

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a1 = -3

the sum of the first n terms of a geometric sequence is

sn = a1×(1 - f^(n+1))/(1-f) for f <>1

so, for f = 2

s7 = 3×(1 - 2⁸)/(1-2) = 3×-255/-1 = 3×255 = 765

for f = -2

s7 = -3×(1 - (-2)⁸)/(1 - -2) = -3×(1-256)/3 = -3×-255/3 =

= -1×-255 = 255

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2 years ago
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Nady [450]

Answer:

Yes

Step-by-step explanation:

16 ÷ 3 = 5.333333...

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3 years ago
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