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kvasek [131]
2 years ago
14

The average height of 5 students is 1.45 m. If one student left the group,the average height of the remaining four of them is 1.

44 m. What was the height of the student who left
Mathematics
1 answer:
SashulF [63]2 years ago
3 0

Answer:

4 students

Step-by-step explanation:

The average = sum of all observations divided by a number of observations. Sum of heights of 4 students = 1.44 ×4 = 5.76. Clearly, height of student who left = Sum of all heights - Sum of heights of 4 students.

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Interpret (1,15)<br><br> interpret (4,60)
statuscvo [17]

Interpreting (1,15) with (4,60), found that (4,60) is 4 times of the coordinate (1,15).

<h3>What are coordinates?</h3>

A pair of numbers that describe the position of a point on a coordinate plane by using the horizontal and vertical distances from the two reference axes.

For interpreting we have to find the relation between (1,15) and (4,60)

We have, (1,15)

For x- coordinate 1, y- coordinate will be 15

Now,

let us take x- coordinate=2 then y- coordinate =30

again, if x-coordinate = 3 then y-coordinate  = 45

lastly, if the x-coordinate =4 then y-coordinate = 60

That means (4,60) is the 4 times of the coordinate (1,15) i.e., the x-coordinate is 4 times as well as the y- coordinate is 4 times.

Learn more about coordinates here:

brainly.com/question/23450276

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4 0
2 years ago
the ratio of the number of shaded sections to the number of unshaded sections is 4 to 2 what is the value of the ratio of the nu
8090 [49]

Answer:

erxytfgnb

Step-by-step explanation:

3 0
3 years ago
Is the following no solution or identity? 2x - 3=-3+2x
Darya [45]

Answer:

2x-3 = 2x-5

because both sides have the same x value ( 2x) this problem has no solution

Step-by-step explanation:

PLZ MARK ME BRAINLYIST

8 0
2 years ago
If a random sample of size nequals=6 is taken from a​ population, what is required in order to say that the sampling distributio
goldenfox [79]

Answer:

\bar X \sim N(\mu , \frac{\sigma}{\sqrt{n}})

In order to satisfy this distribution we need that each observation on this case comes from a normal distribution, because since the sample size is not large enough we can't apply the central limit theorem.

Step-by-step explanation:

For this case we have that the sample size is n =6

The sample man is defined as :

\bar X = \frac{\sum_{i=1}^n X_i}{n}

And we want a normal distribution for the sample mean

\bar X \sim N(\mu , \frac{\sigma}{\sqrt{n}})

In order to satisfy this distribution we need that each observation on this case comes from a normal distribution, because since the sample size is not large enough we can't apply the central limit theorem.

So for this case we need to satisfy the following condition:

X_i \sim N(\mu , \sigma), i=1,2,...,n

Because if we find the parameters we got:

E(\bar X) =\frac{1}{n} \sum_{i=1}^n E(X_i) = \frac{n\mu}{n}=\mu

Var(\bar X)= \frac{1}{n^2} \sum_{i=1}^n Var(X_i) = \frac{n\sigma^2}{n^2}= \frac{\sigma^2}{n}

And the deviation would be:

Sd (\bar X) = \frac{\sigma}{\sqrt{n}}

And we satisfy the condition:

\bar X \sim N(\mu , \frac{\sigma}{\sqrt{n}})

3 0
3 years ago
What value of x and y will make the polygon a parallelogram?
o-na [289]
In a parallelogram, the diagonals bisect each other.
That being the case,
6x = 72

x = 12

AND

x-5 = y
72 -5 = 67

y=67
x = 72

and the diagonals measure
144 and 134
 

5 0
3 years ago
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