Please see pic, I'd solved in it.
The probability that exactly 6 are defective is 0.0792.
Given:
30% of the bulbs in a large box are defective.
If 12 bulbs are selected randomly from the box.
To find:
The probability that exactly 6 are defective.
Solution:
Probability of defective bulbs is:
![p=30\%](https://tex.z-dn.net/?f=p%3D30%5C%25)
![p=\dfrac{30}{100}](https://tex.z-dn.net/?f=p%3D%5Cdfrac%7B30%7D%7B100%7D)
![p=0.3](https://tex.z-dn.net/?f=p%3D0.3)
Probability of non-defective bulbs is:
![q=1-p](https://tex.z-dn.net/?f=q%3D1-p)
![q=1-0.3](https://tex.z-dn.net/?f=q%3D1-0.3)
![q=0.7](https://tex.z-dn.net/?f=q%3D0.7)
The probability that exactly 6 are defective is:
![P(x=r)=^nC_rp^rq^{n-r}](https://tex.z-dn.net/?f=P%28x%3Dr%29%3D%5EnC_rp%5Erq%5E%7Bn-r%7D)
![P(x=6)=^{12}C_6(0.3)^6(0.7)^{12-6}](https://tex.z-dn.net/?f=P%28x%3D6%29%3D%5E%7B12%7DC_6%280.3%29%5E6%280.7%29%5E%7B12-6%7D)
![P(x=6)=924(0.3)^6(0.7)^{6}](https://tex.z-dn.net/?f=P%28x%3D6%29%3D924%280.3%29%5E6%280.7%29%5E%7B6%7D)
![P(x=6)=0.0792478958](https://tex.z-dn.net/?f=P%28x%3D6%29%3D0.0792478958)
![P(x=6)\approx 0.0792](https://tex.z-dn.net/?f=P%28x%3D6%29%5Capprox%200.0792)
Therefore, the probability that exactly 6 are defective is 0.0792.
Learn more:
brainly.com/question/12917164
It has an infinite rotation symmetry because no matter how you rotate the object, it look the same.
Answer:
B i think
Step-by-step explanation:
i think its B because all the other ones don'e look right. hope its correct. :)
Answer:
x
=
7
2
,
−
8
3
Step-by-step explanation: