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2 years ago

Prove that the left side equals to the right side: (sin x/(1-cos x))+(sin x/(1+cos x))=2 csc x

Mathematics

2 answers:

34kurt2 years ago

8 0

sorryy I haven't learned this yet

MAVERICK [17]2 years ago

3 0

Answer:

The left side does not equal to the right side. It's not an identify

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Secants ⎯⎯⎯⎯⎯⎯⎯⎯⎯ and ⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯ intersect in the exterior of a circle. DJH measures 191° and EG measures 53°. Determine the mea

Alik [6]

Answer:

$m\angle EFG =69\degree$

Step-by-step explanation:

$m\angle EFG =\frac{1}{2}(191- 53)\degree$

$m\angle EFG =\frac{1}{2}\times 138\degree$

$m\angle EFG =69\degree$

4 0

3 years ago

......................help

AURORKA [14]

Answer:

50.528º

Step-by-step explanation:

tanA = BC/BA

tanA = 17/14

A = 50.528º

3 0

3 years ago

\A and \B are supplementary angles. If m\A= (3x – 23) and m

mrs_skeptik [129]

2 supplementary angles when added together need to equal 180 degrees.

Add:

3x-23 + 2x-12 = 180

Simplify:

5x -35 = 180

Add 35 to both sides:

5x = 215

Divide both sides by 5:

X = 43

Now replace x with 43 in the equation for angle b:

2(43) -12 = 86-12 = 74 degrees

Angle B = 74 degrees

5 0

3 years ago

Find an equation for the graph

Elanso [62]

Answer:

y=6^x+0.612 - 4

Step-by-step explanation:

x = -4 ---> horizontal asymptote

m = 6 ---> use points (0, -1) and (1, 5)

Parent function of the graph: $y=b^x$

Our equation: $y=6^x$

Add alterations:

Reflections = N/A
Vertical & horizontal shifts = down 4
Vertical & horizontal stretches = left approx 0.612

Final equation: y=6^x+0.612 - 4

6 0

2 years ago

PLEASE HELP ME ANSWER ASAP!

Blizzard [7]

Either twice or more than twice. But I’d go with twice

8 0

3 years ago

Read 2 more answers