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frez [133]
3 years ago
7

A gas cylinder contains 15 moles of 02. How many molecules of oxygen are in the cylinder

Chemistry
1 answer:
Travka [436]3 years ago
3 0

The answer is 9.03 × 10²⁴ molecules of oxygen!

  • <u>Step 1</u>  6.02 × 10²³ molecules : 1 mol = x : 15 mol
  • <u>Step 2</u>  x = 6.02 × 10²³ molecules * 15 mol * 1 mol
  • <u>Step 3</u><em> </em> x = 90.3 × 10²³ molecules
  • <u>Step 4</u>  x = 9.03 × 10 × 10²³ molecules
  • <u>Step 5</u>  x = 9.03 × 10²³⁺¹ molecules
  • <u>Step 6</u>  { x = 9.03 × 10²⁴ molecules }
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tekilochka [14]

Answer:

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Explanation:

When the acetic acid buffer is at pH 5,000; it is possible to obtain the acetate/acetic acid proportions using Henderson-Hasselbalch formula, thus:

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Replacing:

5,000 = 4,740 + log₁₀ [A⁻]/[HA]

1,820 = [A⁻]/[HA] <em>(1)</em>

As buffer concentration is 0,100M:

[A⁻] + [HA] = 0,100 <em>(2)</em>

Replacing (2) in (1)

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As volume is 1,80x10²mL, moles of HA and A⁻ are:

0,180L × 0,035M = <em>6,3x10⁻³mol of HA</em>

0,180L × 0,065M = <em>1,17x10⁻²mol of A⁻</em>

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HCl + A⁻ → HA + Cl⁻

The add moles of HCl are:

0,0065L×0,330M = 2,145x10⁻³ moles of HCl that are equivalent to moles of A⁻ consumed and moles of HA produced.

Thus, moles of HA after addition of HCl are:

6,3x10⁻³mol + 2,145x10⁻³ mol = <em>8,445x10⁻³ moles of HA</em>

And moles of A⁻ are:

1,17x10⁻²mol - 2,145x10⁻³ mol = <em>9,555x10⁻³ moles of A⁻</em>

Replacing these values in Henderson-Hasselbalch formula:

pH = 4,740 + log₁₀ [9,555x10⁻³ ]/[8,445x10⁻³ ]

pH = 4,794

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I hope it helps!

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3 years ago
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Hey there!:

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Volume = 7.5 cm³

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