Answer:
B. PhCHO
Explanation:
Every organic group shows a characteristic IR absorption at certain wavelength . With the help of these absorption spectra we can identify the group present on organic molecules .
The wave number of 2710 cm⁻¹ is absorbed by aldehyde bond stretching .
The wave number of 1705 cm⁻¹ is shown by conjugated aldehyde . So the most likely compound among given compounds is PhCHO .
Because the suffix is -ene. Anything that ends in ene is an alkene.
Answer:
1. C(s) + O₂(g) ⇄ CO₂(g)
2. ![K=\frac{[CO_{2}]}{[O_{2}]}](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B%5BCO_%7B2%7D%5D%7D%7B%5BO_%7B2%7D%5D%7D)
Explanation:
<em>When the oxide of generic metal M is heated at 25.0 °C, a negligible amount of M is produced. MO₂( s ) ⇄ M(s) + O₂(g) ΔG° = 290.2 kJ/mol.</em>
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<em>1. When this reaction is coupled to the conversion of graphite to carbon dioxide, it becomes spontaneous. What is the chemical equation of this coupled process? Show that the reaction is in equilibrium. Include physical states and represent graphite as C(s).</em>
The chemical equation for the coupled reaction is:
C(s) + O₂(g) ⇄ CO₂(g)
<em>2. What is the thermodynamic equilibrium constant for the coupled reaction?</em>
The thermodynamic equilibrium constant (K) is the product of the concentration of the products raised to their stoichiometric coefficients divided by the product of the concentration of the reactants raised to their stoichiometric coefficients. Only gases and aqueous species are included.
![K=\frac{[CO_{2}]}{[O_{2}]}](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B%5BCO_%7B2%7D%5D%7D%7B%5BO_%7B2%7D%5D%7D)
Hey there!
The correct answer is C
Hope this helps you!
Always remember, you are a Work Of Art!
- Nicole :) <3
Answer:
ΔH₁₂ = -867.2 Kj
Explanation:
Find enthalpy for 3H₂ + O₃ => 3H₂O given ...
2H₂ + O₂ => 2H₂O ΔH₁ = -483.6 Kj
3O₂ => 2O₃ ΔH₂ = + 284.6 Kj
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3(2H₂ + O₂ => 2H₂O) => 6H₂ + 3O₂ => 6H₂O (multiply by 3 to cancel O₂)
6H₂ + 3O₂ => 6H₂O ΔH₁ = 3(-483.6 Kj) = -1450.6Kj
2O₃ => 3O₂ ΔH₂ = -284.6Kj (reverse rxn to cancel O₂)
_______________________________
6H₂ + 2O₃ => 6H₂O ΔH₁₂ = -1735.2 Kj (Net Reaction - not reduced)
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divide by 2 => target equation (Net Reaction - reduced)
3H₂ + O₃ => 3H₂O ΔH₁₂ = (-1735.2/2) Kj = -867.2 Kj