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dimulka [17.4K]
3 years ago
13

13299220232+1329220232​

Mathematics
2 answers:
OleMash [197]3 years ago
7 0

Answer:

14628440464

Step-by-step explanation:

denpristay [2]3 years ago
6 0

Answer:

14,628,440,464

Step-by-step explanation:

Perform simple addition.

Glad I was able to help!!

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I need help with this problem, i am confused and don't know what to do.​
klasskru [66]

Problems a through c are asking you what the values would be at those values.

What will the value of f(x) be at x=0? Let's look at the graph.

It seems at x=0, f(x)=0, meaning that f(0)=0

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At x=2, f(2)=-4

For the last question, it is giving us the f(x) value and asking us which x values would give us that.

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Hope this helps.

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3 0
3 years ago
According to geologists, the San Francisco Bay Area experiences five earthquakes with a magnitude of 6.5 or greater every 100 ye
sveta [45]

Answer:

13.53% probability that no earthquakes with a magnitude of 6.5 or greater strike the San Francisco Bay Area in the next 40 years

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given time interval.

According to geologists, the San Francisco Bay Area experiences five earthquakes with a magnitude of 6.5 or greater every 100 years.

One earthquake each 100/5 = 20 years.

What is the probability that no earthquakes with a magnitude of 6.5 or greater strike the San Francisco Bay Area in the next 40 years?

40 years, so \mu = 40/20 = 2

This probability is P(X = 0).

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-2}*2^{0}}{(0)!} = 0.1353

13.53% probability that no earthquakes with a magnitude of 6.5 or greater strike the San Francisco Bay Area in the next 40 years

4 0
3 years ago
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