Radius is normally used for a circle
in a circle, radius is the distance form the center of the circle to the outer edge of the circle
area=legnth times width or in square area=legnth times legneth
since this is a square and this is a math problem, we will assume that radius=1/2legnth so
if radius=16 then legnth =2 times 16=32
area=32 times 32=1042
area=1042 square cm or 1042 cm^2
Answer:
6(26-4)= 132
Step-by-step explanation:
There isn't any variable in the equation
Answer:
- False
- True
-- False
-- True
-- True
Step-by-step explanation:
The points are
,
,
,
and
---- missing from the question
Given

Required
Determine if each of the points would be on 
To do this, we simply substitute the value of x and of each point in
.
(a)
In this case;
and 
becomes




<em>The point </em>
<em> won't be on the graph because the corresponding value of y for </em>
<em> is </em>
<em></em>
(b) 
In this case;


becomes





<em>The point </em>
<em> would be on the graph because the corresponding value of y for </em>
is 
(c) 
In this case:

becomes





<em>The point </em>
<em> wouldn't be on the graph because the corresponding value of y for </em>
<em> is </em>
<em></em>
(d) 
In this case;

becomes


<em>The point </em>
<em> would be on the graph because the corresponding value of y for </em>
is 
(e)
In this case:
; 
becomes




<em>The point </em>
<em> would be on the graph because the corresponding value of y for </em>
is 
If I could give you an answer, I would. But I'm terrible at Math so, sorry
<u>Answer:</u>
The probability of getting two good coils when two coils are randomly selected if the first selection is replaced before the second is made is 0.7744
<u>Solution:</u>
Total number of coils = number of good coils + defective coils = 88 + 12 = 100
p(getting two good coils for two selection) = p( getting 2 good coils for first selection )
p(getting 2 good coils for second selection)
p(first selection) = p(second selection) = 
Hence, p(getting 2 good coil for two selection) = 