Is my answer correct?

Mathematics

1 answer:

GalinKa [24]4 years ago

3 0

Your answer is correct :)

You might be interested in

You need to write 0.63 as a fraciton. How do you choose the denominator?

gladu [14]

You move the decimal over twice to get 63% and then put it over 100, 63/100 to get a fraction

6 0

3 years ago

The length, width, and height of a right rectangular prism are multiplied by 23. What will be the effect on the volume of the pr

Yanka [14]

Since none of the options make sense with 23, I assume it was a typo, and you meant 2/3.

Let l,w and h be the length, width and height of the original prism, and l',w' and h' be the length, width and height of the new prism. We are given

$l' = l\times \cfrac{2}{3},\quad w' = w\times \cfrac{2}{3},\quad h' = h\times \cfrac{2}{3}$

Also, if we call V the original volume, and V' the volume of the new prism, we have

$V = lhw,\quad V'=l'h'w'$

Substitute the expressions for l', h' and w' in the formula for V':

$V'=l'h'w' = l\times \cfrac{2}{3}\times w\times \cfrac{2}{3}\times h\times \cfrac{2}{3} = l\times h \times w \times \cfrac{2}{3}\times\cfrac{2}{3}\times\cfrac{2}{3} = V \times \left(\cfrac{2}{3}\right)^3 = V\times\cfrac{8}{27}$

4 0

3 years ago

The diagram shows an 8-foot ladder leaning against a wall. The ladder makes a 53 degree angle with the wall.

Fittoniya [83]

thats hard lol lolololololololololololollololololololololololololololololololololol

6 0

3 years ago

ou find a deck of cards and know that the deck has too many clubs and spades in it. The deck has 59 cards. If you were to draw t

sashaice [31]

We can find the number of extra clubs in the deck from the given probability, since the probability of drawing a diamond and a club is

$\dfrac{\binom{13}1\binom{13+c}1}{\binom{59}2}=\dfrac{13(13+c)}{1711}$

but this would imply that $c=-4$ , which suggests we're taking 4 clubs out of the original deck and contradicts the problem statement that there are "too many clubs".

Perhaps the question is providing the probability of drawing a diamond, THEN a club, or vice versa. In that case, we have

$\dfrac{\binom{13}1}{\binom{59}1}\cdot\dfrac{\binom{13+c}1}{\binom{58}1}=\dfrac{13(13+c)}{3422}$

and solving gives $c=5$ , which makes more sense. Then the number of extra spades in the deck must be 2.

7 0

3 years ago

Give an example of a rule for a pattern. list a set of numbers that fit the pattern

siniylev [52]

An example is n+2 (n being number).

0,2,4,6,8,10...

4 0

4 years ago