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Rashid [163]
4 years ago
11

Please help me solve this question

Mathematics
1 answer:
Naily [24]4 years ago
8 0
It is alan’s shan’s she’s 12
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How do I find if this type of equation has one solution two solutions or no solution 5x^2+14=19 I tried using the b^-4ac method
mash [69]

Answer:

x = 5 and x = -19

Step-by-step explanation:

You're on the right track.  It's the "discriminant" that tells you what you want to know here.  Before starting, arrange the terms of your quadratic in descending orders of x:  5x^2 + 14x - 19 = 0 (Note that I assumed you meant 14x instead of just 14).

Then the coefficients of this quadratic are a = 5, b = 14 and c = -19.

You are referring to the "quadratic formula."  It states this:

      -b ± √(b²-4ac)

x = -----------------------

               2a                                        

So, we insert the a, b and c values as indicated above:

      -14 ± √( 14² - 4[5][-19] )        -14 ± √(196 - 4[5][-19] )        -14 ± √576

x = ----------------------------------- = ---------------------------------- = ----------------------

                 2(10)                                 20                                      20

This comes out to:

x = (-14 + 24) / 2      and     x = (-14 - 24) / 2

or:

x = 5 and x = -19

8 0
4 years ago
Is anyone good at math on the top of their head pls comment below ASAP!!!
saul85 [17]

Answer:

please do you need help there are more expect around

Step-by-step explanation:

drop the question let help you

4 0
3 years ago
Read 2 more answers
13. How many distinct 4-letter groupings can be made with the letters from the word champion if letters may not be repeated?
ddd [48]

Answer:

N = 1680

Therefore, 1680 '4 letter groupings' can be formed from the word 'champion'

Step-by-step explanation:

Given the word 'champion' which is an 8 distinct Letter word. The number of 4 letter groupings that could be formed from it can be given by the permutation since in this case order of letters are important.

The number of distinct 4 letter groupings can be given as;

N = nPr = 8!/(8-4)!, where n= 8 and r = 4

N = 8P4 = 8!/(8-4)!

N= 8!/4!

N = 1680

Therefore, 1680 '4 letter groupings' can be formed from the word 'champion'

7 0
4 years ago
A+b/c=d/4 solve for a
RUDIKE [14]

Answer:

a = d/4 - b/c

Step-by-step explanation:

Subtract b/c from both sides. We can subtract a fraction

so

a = d/4 - b/c

8 0
3 years ago
Find the circumference of the circle.Use 3.14 for pi<br> 14 ft
Ber [7]
<h2>circumference = 87.92ft</h2>

Step-by-step explanation:

radius (r) = 14ft

circumference = 2π×r

= 2 × 3.12 × 14

= 87.92ft

<h2>MARK ME BRAINLIST</h2>
4 0
3 years ago
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