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Contact [7]
2 years ago
15

Our environment is very sensitive to the amount of ozone in the upper atmosphere. The level of ozone normally found is 6.8 parts

/million (ppm). A researcher believes that the current ozone level is at an insufficient level. The mean of 10 samples is 6.4 ppm with a standard deviation of 1.1. Does the data support the claim at the 0.05 level
Mathematics
1 answer:
Gnoma [55]2 years ago
5 0

Answer:

The test statistics fall in the critical region and hence null hypothesis is to be rejected.

Step-by-step explanation:

The null hypothesis : H0 : Mean = 6.80  

Alternative hypothesis: Ha: Mean is not equal to 6.80

As per the z statistics  

z = (x’-mean)/(sigma/sqrt n)

Substituting the given values, we get –  

z = 6.4-6.8/(1.1/sqrt 10)

z = -1.149

z test statistics is -1.149

Critical value for two tailed test at 98% confidence is .10749

The test statistics fall in the critical region and hence null hypothesis is to be rejected.

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Sherry is driving 390 miles to visit The gateway arch in St. Louis. She drives at an average rate of 65 miles per hour. Explain
grandymaker [24]

Answer:

t = 6 s

Step-by-step explanation:

Given that,

Sherry is driving 390 miles to visit The gateway arch in St. Louis.

She drives at an average rate of 65 miles per hour.

We need to find the amount of time it will take Sherry to get to the arch. Let the time is t.

Speed = distance/time

t=\dfrac{d}{v}\\\\t=\dfrac{390}{65}\\\\t=6\ h

Hence, it will take 6 hours to get to the arch.

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3 years ago
70 miles = ______ kilometers
vampirchik [111]
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4 0
3 years ago
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For what values of θ on the polar curve r=θ, with 0≤θ≤2π , are the tangent lines horizontal? Vertical?
Bond [772]
Given that r=\theta, then r'=1

The slope of a tangent line in the polar coordinate is given by:

m= \frac{r'\sin\theta+r\cos\theta}{r'\cos\theta-r\sin\theta}

Thus, we have:

m= \frac{\sin\theta+\theta\cos\theta}{\cos\theta-\theta\sin\theta}



Part A:

For horizontal tangent lines, m = 0.

Thus, we have:

\sin\theta+\theta\cos\theta=0 \\  \\ \theta\cos\theta=-\sin\theta \\  \\ \theta=- \frac{\sin\theta}{\cos\theta} =-\tan\theta

Therefore, the <span>values of θ on the polar curve r = θ, with 0 ≤ θ ≤ 2π, such that the tangent lines are horizontal are:

</span><span>θ = 0

</span>θ = <span>2.02875783811043
</span>
θ = <span>4.91318043943488



Part B:

For vertical tangent lines, \frac{1}{m} =0

Thus, we have:

\cos\theta-\theta\sin\theta=0 \\  \\ \Rightarrow\theta\sin\theta=\cos\theta \\  \\ \Rightarrow\theta= \frac{\cos\theta}{\sin\theta} =\sec\theta

</span>Therefore, the <span>values of θ on the polar curve r = θ, with 0 ≤ θ ≤ 2π, such that the tangent lines are vertical are:

</span>θ = <span>4.91718592528713</span>
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Answer is A............
5 0
2 years ago
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If you multiply 5(2x+3+4y), the answer is ______
Volgvan

Answer:

You don't even need to do the whole question. Just look at 5 times 2x. which is 10x then u get your answer

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