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liraira [26]
3 years ago
13

Round to the nearest thousandth. 1.0835

Mathematics
2 answers:
Ne4ueva [31]3 years ago
5 0

Answer:

It would be 1.084

charle [14.2K]3 years ago
4 0

Answer:

1.0840

Step-by-step explanation:

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Look at the bottom of the pictures to see what number it is
kondaur [170]

Step-by-step explanation:

hence the value of y=-9/4and k=-16.

3 0
3 years ago
Twice a number x increased by 10 is 52
musickatia [10]

Answer:

x = 21

Step-by-step explanation:

the equation is 2x + 10 = 52

2x = 42

x = 21

4 0
3 years ago
Solve the equation. Then check your solution. 5 /9 d = 9 /10 a. 31 / 90 c. 1/2 b. 1 31 /90 d. 50 /81
miskamm [114]

Answer:

d in (-oo:+oo)

(5/9)*d = 9/10 // - 9/10

(5/9)*d-(9/10) = 0

(5/9)*d-9/10 = 0

5/9*d-9/10 = 0 // + 9/10

5/9*d = 9/10 // : 5/9

d = 9/10/5/9

d = 81/50

d = 81/50

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
1.) Consider the right triangle below in which a = 5 and b = 5.
patriot [66]

Answer:

c=7.07

Step-by-step explanation:

c²=a²+b²

c²=5²+5²

c²=25+25

c²=50

c=√50

c=7.07

B. c=7.07 (to nearest hundredth)

C. c=√50= 5√2 in radical form

3 0
2 years ago
Let E = {(x, y) e R2|xy > 0}. Determine whether E is a subspace of R2 . X3
gayaneshka [121]

Answer:

E is not a subspace of \mathbb{R}^2

Step-by-step explanation:

E is not a subspace of  \mathbb{R}^2

In order to see this, we must find two points (a,b), (c,d) in  E such that (a,b) + (c,d) is not in E.

Consider

(a,b) = (1,1)

(c,d) = (-1,-1)

It is easy to see that both (a,b) and (c,d) are in E since 1*1>0 and (1-)*(-1)>0.  

But (a,b) + (c,d) = (1-1, 1-1) = (0,0)

and (0,0) is not in E.

By the way, it can be proved that in any vector space all sub spaces must have the vector zero.

5 0
3 years ago
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