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soldi70 [24.7K]
3 years ago
6

Perimeter of a rectangle is 15x+17y if the length is 7/2x+7y then find the width of the rectangle

Mathematics
1 answer:
bogdanovich [222]3 years ago
8 0

The perimeter of a rectangle is given by the formula,


P=2l+2w


We substitute,


P=15x+17y


and


l=\frac{7}{2}x+7y


into the above formula to obtain the expression,




15x+17y=2(\frac{7}{2}x+7y)+2w



15x+17y=7x+14y+2w




We now group the x and y terms on the Left Hand Side of the equation to get.


15x-7x+17y-14y=2w




8x+7y=2w



We now divide through by 2 to get,



4x+\frac{7}{2}y=w



Therefore the width of the rectangle is


4x+\frac{7}{2}y



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Answer:

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Step-by-step explanation:

let x represent the amount of kids and y represent the amount of adults.

since the problem says there was a total of 220 people at the fair an equation can be made

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the problem tells that each childrens ticket was 1.5$ and each adult ticket was $4 and that a total of $550 was made that day, we can use the knowledge to make an equation:

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using the equations we can make this systems of equations:

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Answer:

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In ΔQRS,

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See the diagram below.

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