All categories

3 years ago

Perimeter of a rectangle is 15x+17y if the length is 7/2x+7y then find the width of the rectangle

Mathematics

1 answer:

bogdanovich [222]3 years ago

8 0

The perimeter of a rectangle is given by the formula,

$P=2l+2w$

We substitute,

$P=15x+17y$

and

$l=\frac{7}{2}x+7y$

into the above formula to obtain the expression,

$15x+17y=2(\frac{7}{2}x+7y)+2w$

$15x+17y=7x+14y+2w$

We now group the x and y terms on the Left Hand Side of the equation to get.

$15x-7x+17y-14y=2w$

$8x+7y=2w$

We now divide through by 2 to get,

$4x+\frac{7}{2}y=w$

Therefore the width of the rectangle is

$4x+\frac{7}{2}y$

You might be interested in

Hello everyone… Please answer … Let's solve a little logic : )

morpeh [17]

Answer:

Step-by-step explanation:

6 0

3 years ago

What does | | represent?

RSB [31]

It represente the absolute value

7 0

3 years ago

Suppose that X has an exponential distribution with mean equal to 10. Determine the following: a. P(X > 10) b. P(X > 20) c

GrogVix [38]

Answer:

(a) The value of P (X > 10) is 0.3679.

(b) The value of P (X > 20) is 0.1353.

(d) The value of x is 30.

Step-by-step explanation:

The probability density function of an exponential distribution is:

$f(x)=\lambda e^{-\lambda x};\ x>0, \lambda>0$

The value of E (X) is 10.

The parameter λ is:

$\lambda=\frac{1}{E(X)}=\frac{1}{10}=0.10$

(a)

Compute the value of P (X > 10) as follows:

$P(X>10)=\int\limits^{\infty}_{10} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{10} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{10}\\=|e^{-0.10 x} |^{\infty}_{10}\\=e^{-0.10\times10}\\=0.3679$

Thus, the value of P (X > 10) is 0.3679.

(b)

Compute the value of P (X > 20) as follows:

$P(X>20)=\int\limits^{\infty}_{20} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{20} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{20}\\=|e^{-0.10 x} |^{\infty}_{20}\\=e^{-0.10\times20}\\=0.1353$