Question

Perimeter of a rectangle is 15x+17y if the length is 7/2x+7y then find the width of the rectangle

Answer 1

The perimeter of a rectangle is given by the formula,

$P=2l+2w$

We substitute,

$P=15x+17y$

and

$l=\frac{7}{2}x+7y$

into the above formula to obtain the expression,

$15x+17y=2(\frac{7}{2}x+7y)+2w$

$15x+17y=7x+14y+2w$

We now group the x and y terms on the Left Hand Side of the equation to get.

$15x-7x+17y-14y=2w$

$8x+7y=2w$

We now divide through by 2 to get,

$4x+\frac{7}{2}y=w$

Therefore the width of the rectangle is

$4x+\frac{7}{2}y$