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VMariaS [17]
3 years ago
13

Solve the inequality. y/-6 > 10 . a. y -60 c. y > 4 d. y

Mathematics
2 answers:
Iteru [2.4K]3 years ago
8 0
If you would like to solve the inequality y/(-6) > 10, you can calculate this using the following steps:

y/(-6) > 10      /*6
- y > 10 * 6
- y > 60         /*(-1)
y < - 60

The correct result would be a. y < - 60.
anzhelika [568]3 years ago
6 0
\frac{y}{-6} \ \textgreater \ 10\\\\Multiply\ by\ -6\ on\ both\ siddes.\ This\ will\ switch\ the\ sign\ around\\because\ of\ the\ negative\ sign.\\\\\sf\ ANSWER:\ {\boxed{y\ \textless \ -60}

ANSWER: A
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A coffee packaging plant claims that the mean weight of coffee in its containers is at least 32 ounces. A random sample of 15 co
Luda [366]

Answer:

We conclude that the mean weight of coffee in its containers is at least 32 ounces which means that the data support the claim.

Step-by-step explanation:

We are given that a coffee packaging plant claims that the mean weight of coffee in its containers is at least 32 ounces.

A random sample of 15 containers were weighed and the mean weight was 31.8 ounces with a sample standard deviation of 0.48 ounces.

Let \mu = <u><em>mean weight of coffee in its containers.</em></u>

SO, Null Hypothesis, H_0 : \mu \geq 32 ounces     {means that the mean weight of coffee in its containers is at least 32 ounces}

Alternate Hypothesis, H_A : \mu < 32 ounces      {means that the mean weight of coffee in its containers is less than 32 ounces}

The test statistics that would be used here <u>One-sample t-test statistics</u> as we don't know about population standard deviation;

                             T.S. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean weight = 31.8 ounces

             s = sample standard deviation = 0.48 ounces

             n = sample of containers = 15

So, <u><em>the test statistics</em></u>  =  \frac{31.8 -32}{\frac{0.48}{\sqrt{15} } }  ~ t_1_4  

                                      =  -1.614

The value of t test statistics is -1.614.

<u>Now, at 0.01 significance level the t table gives critical value of -2.624 at 14 degree of freedom for left-tailed test.</u>

Since our test statistic is more than the critical value of t as -1.614 > -2.624, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <u><em>we fail to reject our null hypothesis</em></u>.

Therefore, we conclude that the mean weight of coffee in its containers is at least 32 ounces which means that the data support the claim.

8 0
4 years ago
THIS IS THE T H I R D TIME IVE POSTED THIS P L E A S E ANSWER
Goshia [24]

Find common denominators. 10 is the common denominator. Multiply 2 to numerator and denominator of -3/5

(-3/5)(2/2) = -6/10

x + 1/10 = -6/10

Isolate the x. Subtract 1/10 from both sides

x + 1/10 (-1/10) = -6/10 (-1/10)

x = -6/10 - 1/10

x = -7/10

-7/10 is your answer for x

hope this helps

4 0
3 years ago
Which scenario would result in 12 possible outcomes?
Gnesinka [82]

Answer:

You roll a number cube, and then you flip a coin.

Step-by-step explanation:

i don't even know how math is confusing. (this is the right answer on the quiz)

5 0
3 years ago
What is the radius and diameter of the following circle
son4ous [18]
Radius is 11cm
diameter is 22cm
7 0
3 years ago
Steven has 1/3 of package of biscuit mix left.He will use equal para of the leftover mix to make three watches of biscuits. If h
Nuetrik [128]

Answer:

1/9

Step-by-step explanation:

(1/3)/3 = 1/9

3 0
3 years ago
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