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3 years ago

Solve the inequality. y/-6 > 10 . a. y -60 c. y > 4 d. y

2 answers:

8 0

If you would like to solve the inequality y/(-6) > 10, you can calculate this using the following steps:

y/(-6) > 10 /*6
- y > 10 * 6
- y > 60 /*(-1)
y < - 60

The correct result would be a. y < - 60.

anzhelika [568]3 years ago

6 0

$\frac{y}{-6} \ \textgreater \ 10\\\\Multiply\ by\ -6\ on\ both\ siddes.\ This\ will\ switch\ the\ sign\ around\\because\ of\ the\ negative\ sign.\\\\\sf\ ANSWER:\ {\boxed{y\ \textless \ -60}$

ANSWER: A

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10. In a survey of 212 people at the local track and field championship, 72% favored the home team

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Answer:

a. The margin of error for the survey is of 0.0308 = 3.08%.

b. The 95% confidence interval that is likely to contain the exact percent of all people who favor the home team winning is (65.96%, 78.04%).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the z-score that has a p-value of $1 - \frac{\alpha}{2}$ .

The margin of error of the survey is:

$M = \sqrt{\frac{\pi(1-\pi)}{n}}$

The confidence interval can be written as:

$\pi \pm zM$

In a survey of 212 people at the local track and field championship, 72% favored the home team winning.

This means that $n = 212, \pi = 0.72$

a. Find the margin of error for the survey.

$M = \sqrt{\frac{0.72*0.28}{212}} = 0.0308$

The margin of error for the survey is of 0.0308 = 3.08%.

b. Give the 95% confidence interval that is likely to contain the exact percent of all people who favor the home team winning.

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a p-value of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

Lower bound:

$\pi - zM = 0.72 - 1.96*0.0308 = 0.6596$

Upper bound:

$\pi + zM = 0.72 + 1.96*0.0308 = 0.7804$

As percent:

0.6596*100% = 65.96%

0.7804*100% = 78.04%.

The 95% confidence interval that is likely to contain the exact percent of all people who favor the home team winning is (65.96%, 78.04%).

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3 years ago

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Answer:

Step-by-step explanation:

The 3 is in the tens place representing the number 30.

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Answer:

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