Answer:
For this case we want to check if the true mean for the depth of groves cut into aluminium by a machine is equal to 1.7 (null hypothesis) and the alternative hypothesis would be the complement different from 1.7. And the best system of hypothesis are:
Null hypothesis: 
Alternative hypothesis ![\mu \neq 1.7[/tx]And the best system of hypothesis are:3. This two-sided test: H0: μ = 1.7 mm H1: μ ≠ 1.7 mmStep-by-step explanation:For this case we want to check if the true mean for the depth of groves cut into aluminium by a machine is equal to 1.7 (null hypothesis) and the alternative hypothesis would be the complement different from 1.7. And the best system of hypothesis are:Null hypothesis: [tex]\mu =1.7](https://tex.z-dn.net/?f=%5Cmu%20%5Cneq%201.7%5B%2Ftx%5D%3C%2Fp%3E%3Cp%3EAnd%20the%20best%20system%20of%20hypothesis%20are%3A%3C%2Fp%3E%3Cp%3E3.%20This%20two-sided%20test%3A%0A%3C%2Fp%3E%3Cp%3EH0%3A%20%CE%BC%20%3D%201.7%20mm%0A%3C%2Fp%3E%3Cp%3EH1%3A%20%CE%BC%20%E2%89%A0%201.7%20mm%3C%2Fp%3E%3Cp%3E%3Cstrong%3EStep-by-step%20explanation%3A%3C%2Fstrong%3E%3C%2Fp%3E%3Cp%3EFor%20this%20case%20we%20want%20to%20check%20if%20the%20true%20mean%20for%20the%20depth%20of%20groves%20cut%20into%20aluminium%20by%20a%20machine%20is%20equal%20to%201.7%20%28null%20hypothesis%29%20and%20the%20alternative%20hypothesis%20would%20be%20the%20complement%20different%20from%201.7.%20And%20the%20best%20system%20of%20hypothesis%20are%3A%3C%2Fp%3E%3Cp%3ENull%20hypothesis%3A%20%5Btex%5D%5Cmu%20%3D1.7)
Alternative hypothesis [tex]\mu \neq 1.7[/tx]
And the best system of hypothesis are:
3. This two-sided test:
H0: μ = 1.7 mm
H1: μ ≠ 1.7 mm
2. (D)
3. (B) Hope it helps
Well, notice the composite is really just 4 triangles atop sitting on top of 4 rectangles, and all of them area stacked up at the edges.
so, for the rectangle's sides,
front and back are two 6x3 rectangles
left and right are two 6x3 rectangles
the bottom part is a 6x6 rectangle
now, we don't include the 6x6 rectangle that's touching the triangles, because that's inside area, and is not SURFACE area, so we nevermind that one.
now, the triangles are just four triangles with a base of 6, and a height of 4, in red noted there.
so, just get the area of all those rectangles and the triangles, sum them up and that's the
surface area of the composite,
Answer is
<span>C. 128 + 8.50x + 9.50y + 10z
hope it helps</span>
Answer:
10/3
Step-by-step explanation:
The answer would be 10/3. Please mark brainliest!
