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ivanzaharov [21]

3 years ago

13

The area of rectangle a is 11 over 12 square meters the area of rectangle b is 8 over 12 square meters how much larger is rectan

gle a

1 answer:

Kaylis [27]3 years ago

3 0

A is 8 x 12 so...

54

thanks for using Brainly!

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Find the value of x

Alekssandra [29.7K]

Answer:

x=12

Step-by-step explanation: brainest pls

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2 years ago

Find the perimeter of each figure. Simplify.

Kay [80]

Answer:

5)14x+4

6)20x

Step-by-step explanation:

5)8x+6x+4

6) 5x×4

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3 years ago

Use the divergence theorem to calculate the surface integral s f · ds; that is, calculate the flux of f across s. f(x, y, z) = x

valkas [14]

$\mathbf f(x,y,z)=x^4\,\mathbf i-x^3z^2\,\mathbf j+4xy^2z\,\mathbf k$
$\mathrm{div}(\mathbf f)=\dfrac{\partial(x^4)}{\partial x}+\dfrac{\partial(-x^3z^2)}{\partial y}+\dfrac{\partial(4xy^2z)}{\partial z}=4x^3+0+4xy^2=4x(x^2+y^2)$

Let $\mathcal D$ be the region whose boundary is $\mathcal S$ . Then by the divergence theorem,

$\displaystyle\iint_{\mathcal S}\mathbf f\cdot\mathrm d\mathbf S=\iiint_{\mathcal D}4x(x^2+y^2)\,\mathrm dV$

Convert to cylindrical coordinates, setting

$x=r\cos\theta$
$y=r\sin\theta$

and keeping $z$ as is. Then the volume element becomes

$\mathrm dV=r\,\mathrm dr\,\mathrm d\theta\,\mathrm dz$

and the integral is

$\displaystyle\iiint_{\mathcal D}4x(x^2+y^2)\,\mathrm dV=\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=1}\int_{z=0}^{z=r\cos\theta+7}4r\cos\theta\cdot r^2\cdot r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta$
$=\displaystyle4\iiint_{\mathcal D}r^4\cos\theta\,\mathrm dz\,\mathrm dr\,\mathrm d\theta$
$=\dfrac{2\pi}3$

4 0

4 years ago

Please help me find the answer

Ksivusya [100]

Answer:

-4 1/4

Step-by-step explanation:

-7 3/4 + 3 1/2 = -4 1/4

8 0

3 years ago

Y=1/3mx^3 – (m–1)x^2 + 3(m–2)x +1/3

ValentinkaMS [17]

Answer:

not true

Step-by-step explanation:

i just wants points mate

8 0

3 years ago