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3 years ago

How do I solve this?

Mathematics

2 answers:

Mariulka [41]3 years ago

8 0

The min is x= -b/2a

X=-30/2(3)

-30/6= -5

7nadin3 [17]3 years ago

3 0

The minimum happens at x = -b/2a

x = -30 / 2(3) = -30/6 = -5

Now replace x in the equation with -5 and solve:

3(-5)^2 + 30(-5) +27 = 75 - 150 + 27 = -48

The minimum is at (-5,-48)

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Step-by-step explanation:

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y = Acos(Bx)

From the graph attached,

A = Amplitude = $\frac{1-(-1)}{2}$

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B = $\frac{2\pi}{\frac{\pi}{2}-0}$

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Answer:

9.6

Step-by-step explanation:

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Suppose you have $75 to spend on gas for your whole trip. You know that gas costs $3.40 per gallon. How many gallons of gas can

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3 years ago

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Brand Number of Packets Cost

mash [69]

Brand 2 is the best value ⇒ B

Step-by-step explanation:

Let us write the Brand, Number of Packets and Cost

→ Brand : Number of Packets : Cost
→ 1 : 12 : $10.68
→ 2 : 16 : $9.44
→ 3 : 18 : $15.30
→ 4 : 24 : $21.84
→ 5 : 30 : $20.40

We need to find what brand is the best value

To find that let us find the price of each packet in each brand, by dividing the price of the brand by the number of the packets, the cheapest price is the best

∵ Brand 1 has 12 packets

∵ The price of Brand 1 is $10.68

∴ The price of each packet = 10.68 ÷ 12 = 0.89

∴ The price of each packet in Brand 1 is $0.89

∵ Brand 2 has 16 packets

∵ The price of Brand 2 is $9.44

∴ The price of each packet = 9.44 ÷ 16 = 0.59

∴ The price of each packet in Brand 2 is $0.59

∵ Brand 3 has 18 packets

∵ The price of Brand 3 is $15.30

∴ The price of each packet = 15.30 ÷ 18 = 0.85

∴ The price of each packet in Brand 3 is $0.85

∵ Brand 4 has 24 packets

∵ The price of Brand 4 is $21.84

∴ The price of each packet = 21.84 ÷ 24 = 0.91

∴ The price of each packet in Brand 4 is $0.91

∵ Brand 5 has 30 packets

∵ The price of Brand 5 is $20.40

∴ The price of each packet = 20.40 ÷ 30 = 0.68

∴ The price of each packet in Brand 5 is $0.68

∵ The least price of a packet is in Brand 2

∴ The cheapest price is Brand 2

Brand 2 is the best value

Learn more:

You can learn more about the word problems in brainly.com/question/2686310

#LearnwithBrainly

8 0

3 years ago