3 years ago

How do I solve this?

Mathematics

2 answers:

Mariulka [41]3 years ago

8 0

The min is x= -b/2a

X=-30/2(3)

-30/6= -5

7nadin3 [17]3 years ago

3 0

The minimum happens at x = -b/2a

x = -30 / 2(3) = -30/6 = -5

Now replace x in the equation with -5 and solve:

3(-5)^2 + 30(-5) +27 = 75 - 150 + 27 = -48

The minimum is at (-5,-48)

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