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sergiy2304 [10]
3 years ago
9

When someone purchases a new car and begins to drive it, generally speaking, the resale value of the car (in dollars) goes down

each year. Let represent the number of years since purchase and represent the resale value of thecar (in dollars). The linear function that models the resale value based on the number of years since purchase is y = 32000 - 3500x. What can we say about the rate of change and the initial value? Answer fast please 25pts. multiple choice.
A.The rate of change is 32000 and the the initial value is -3500. $32000 represents the decrease of value per year and -3500 represents the initial value of the car.


B.The rate of change is 3500 and the initial value is 32000. 3500 means that the car increases its value by $3500 every year and the initial value is $32000.


C,The rate of change is -3500 and the initial value is 32000. -3500 represents the initial value of the car.


D.The rate of change is -3500 and the initial value is 32000. 32,000 represents the initial value of the car and -3500 is the decrease in value of the car every year.
Mathematics
1 answer:
Sphinxa [80]3 years ago
7 0

Answer:

D

Step-by-step explanation:

$32000 initial value

-3500 every year after purchase  

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Solve: 3x - 7 - 2x + 5 = 6 A) -8 B) - 18 5 C) 4 D) 8
seropon [69]

Answer:

D) 8

Step-by-step explanation:

3x - 7 - 2x + 5 = 6

3x - 2x  = 6 + 7 - 5

  x   = 8

Note: 6 + 7 -5 =  13 -5 = 8

7 0
3 years ago
Determine whether the given system has a unique solution, no solution, or infinitely many solutions.
victus00 [196]

Answer:

The system has no solution.

Step-by-step explanation:

To find the solution to this system of linear equations

\left\begin{array}{ccccc}-3x_1&+x_2&-2x_3&=&8&\\x_1&+5x_2&-x_3&=&4&\\-x_1&+11x_2&-4x_3&=&1&\end{array}\right

First, state the problem in matrix form, this means, extracting only the numbers, and putting them in a box.

\left[ \begin{array}{ccc|c} -3 & 1 & -2 & 8 \\\\ 1 & 5 & -3 & 4 \\\\ -1 & 11 & -4 & 1 \end{array} \right]

This is called an augmented matrix. The word “augmented” refers to the vertical line, which we draw to remind ourselves where the equals sign belong

Next, transform the augmented matrix to the reduced row echelon form with the help of Row Operations.

Row Operation 1: multiply the 1st row by -1/3

\left[ \begin{array}{ccc|c} 1 & - \frac{1}{3} & \frac{2}{3} & - \frac{8}{3} \\\\ 1 & 5 & -1 & 4 \\\\ -1 & 11 & -4 & 1 \end{array} \right]

Row Operation 2: add -1 times the 1st row to the 2nd row

\left[ \begin{array}{ccc|c} 1 & - \frac{1}{3} & \frac{2}{3} & - \frac{8}{3} \\\\ 0 & \frac{16}{3} & - \frac{5}{3} & \frac{20}{3} \\\\ -1 & 11 & -4 & 1 \end{array} \right]

Row Operation 3: add 1 times the 1st row to the 3rd row

\left[ \begin{array}{ccc|c} 1 & - \frac{1}{3} & \frac{2}{3} & - \frac{8}{3} \\\\ 0 & \frac{16}{3} & - \frac{5}{3} & \frac{20}{3} \\\\ 0 & \frac{32}{3} & - \frac{10}{3} & - \frac{5}{3} \end{array} \right]

Row Operation 4: multiply the 2nd row by 3/16

\left[ \begin{array}{ccc|c} 1 & - \frac{1}{3} & \frac{2}{3} & - \frac{8}{3} \\\\ 0 & 1 & - \frac{5}{16} & \frac{5}{4} \\\\ 0 & 0 & 0 & -15 \end{array} \right]

Row Operation 5: add -32/3 times the 2nd row to the 3rd row

\left[ \begin{array}{ccc|c} 1 &- \frac{1}{3}  & \frac{2}{3} & - \frac{8}{3} \\\\ 0 & 1 & - \frac{5}{16} & \frac{5}{4} \\\\ 0 & 0 & 0 & -15 \end{array} \right]

Row Operation 6: multiply the 3rd row by -1/15

\left[ \begin{array}{ccc|c} 1 &- \frac{1}{3}  & \frac{2}{3} & - \frac{8}{3} \\\\ 0 & 1 & - \frac{5}{16} & \frac{5}{4} \\\\ 0 & 0 & 0 & 1 \end{array} \right]

Row Operation 7: add -5/4 times the 3rd row to the 2nd row

\left[ \begin{array}{ccc|c} 1 &- \frac{1}{3}  & \frac{2}{3} & - \frac{8}{3} \\\\ 0 & 1 & - \frac{5}{16} & 0 \\\\ 0 & 0 & 0 & 1 \end{array} \right]

Row Operation 8: add 8/3 times the 3rd row to the 1st row

\left[ \begin{array}{ccc|c} 1 &- \frac{1}{3}  & \frac{2}{3} & 0 \\\\ 0 & 1 & - \frac{5}{16} & 0 \\\\ 0 & 0 & 0 & 1 \end{array} \right]

Row Operation 9: add 1/3 times the 2nd row to the 1st row

\left[ \begin{array}{cccc} 1 & 0 & \frac{9}{16} & 0 \\\\ 0 & 1 & - \frac{5}{16} & 0 \\\\ 0 & 0 & 0 & 1 \end{array} \right]

The reduced row echelon form of the augmented matrix is

\left[ \begin{array}{cccc} 1 & 0 & \frac{9}{16} & 0 \\\\ 0 & 1 & - \frac{5}{16} & 0 \\\\ 0 & 0 & 0 & 1 \end{array} \right]

which corresponds to the system

\left\begin{array}{ccccc}x_1&&+\frac{9}{16} x_3&=&0&\\&1x_2&-\frac{5}{16}x_3&=&0&\\&&0&=&1&\end{array}\right

Equation 3 cannot be solved, therefore, the system has no solution.

7 0
3 years ago
dylan started working on homework at 5:45 p.m. it took him 1 hour and 57 minutes to complete it what time did
kkurt [141]

I'm assuming its asking what time he finished? I added it up and it seems to be 7:42 pm.

5 0
3 years ago
What is 1.58 in standard form?
ella [17]
1 one and 58 hundredths.

I hope you like this answer, and have a good night and life! :D
8 0
4 years ago
Find the volume of the square pyramid shown. Round to the nearest cubic foot.
Alik [6]

Answer:

3840 ft³

Step-by-step explanation:

Volume of a pyramid = 1/3( base area x height)

Base area = area of a square

area of square = length²

= 24² = 576

volume = 1/3(576 x 20) = increases as the price falls

5 0
3 years ago
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