30 pints of first type and 130 pints of second type drinks must be used to make the mixture.
<em><u>Explanation</u></em>
Lets assume, the amount of first type drink is
pints.
As the total amount of the mixture is 160 pints, so the amount of second type drink
pints.
The first type is 20% pure juice, the second type is 100% pure fruit juice and the mixture is 85% pure fruit juice. So the equation will be .....

So, the amount of first type drink is 30 pints and the amount of second type drink is (160-30)pints =130 pints.
Answer:
40.3 m
Step-by-step explanation:
a²+b²=c²
40²+5²=c²
1600+25= 1625
√1625 = 40.3112
Answer: 0.965
Step-by-step explanation:
Given : Water use in the summer is normally distributed with


Let X be the random variable that represents the quantity of water required on a particular day.
Z-score : 

Now, the probability that a day requires more water than is stored in city reservoirs is given by:-

We can see that on comparing the above value to the given P(X > 350)= 1 - P(Z < b) , we get the value of b is 0.965.
Answer:
The lateral area is 392.5 sq. inches.
Step-by-step explanation:
The pipe is in a shape of a cylinder. The lateral area formula for a cylinder is:
Lateral Area = 
Where
r is the radius (half of diameter)
h is the height
Given, diameter = 5
so,
radius = 5/2 = 2.5
Also,
height = 25 inches (same as length, here)
Now we use 3.14 for
and substitute the values to get the lateral area:
Lateral Area = 
The lateral area is 392.5 sq. inches.
Answer:
1,12×10^6
Step-by-step explanation: