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Sergeeva-Olga [200]
3 years ago
14

What the answer can y’all hell me

Chemistry
1 answer:
lakkis [162]3 years ago
3 0

Answer: The answer would be: (B) Cast-off

Note: Hope this helps :) Good luck!

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The answer is "can gravity exhaust"
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What is the ratio of the side lengths on polygon FGHIJ to the corresponding side lengths on polygon ABCDE? Enter the ratio in th
alukav5142 [94]

Explanation:

this is the exact answer!!

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Consider the following chemical equilibrium:
jok3333 [9.3K]

Answer:

Kc = [CH₄] / [H₂]²

Kp = [CH₄] / [H₂]² * (0.082*T)^-1

Explanation:

Equilibrium constant, Kc, is defined as the ratio of the concentrations of the products over the reactants. Also, each concentration of product of reactant is powered to its coefficient.

<em>Pure solids and liquids are not taken into account in an equilibrium</em>

Thus, for the reaction:

C(s)+ 2H₂(g) ⇌ CH₄(g)

Equilibrium constant is:

<h3>Kc = [CH₄] / [H₂]²</h3>

Now, using the formula:

Kp = Kc* (RT)^Δn

<em>Where R is gas constant (0.082atmL/molK), T is the temperature of the reaction and Δn is difference in coefficients of gas products - coefficients of gas reactants (1 - 2= -1)</em>

Replacing:

<h3>Kp = [CH₄] / [H₂]² * (0.082*T)^-1</h3>

<em />

4 0
3 years ago
How many ml of 12.0 M H2S04 are needed to make 500.0 ml of a 1.00 M solution? What happens to the freezing point and the boiling
lora16 [44]

Answer:

41.66 mL of 12.0 M sulfuric acid are needed.

Explanation:

Concentration of sulfuric acid solution taken =M_1=12.0M

Volume of the 12.0 M Solution = V_1

Concentration of required solution = M_2=1.00M

Volume of required 1.00 M solution = V_2=500.0 mL

M_1V_1=M_2V_2 (Dilution)

V_1=\frac{1.00 M\times 500.0 mL}{12.0 M}=41.66 mL

41.66 mL of 12.0 M sulfuric acid are needed.

The freezing point and the boiling point of a solvent when a non-volatile solute is dissolved in it decrease and increase respectively.

3 0
4 years ago
Which substance could store more energy on a per gram basis, sodium thiosulfate pentahydrate or sodium chloride?
geniusboy [140]
Sodium Chloride is 0.4948 kJ/mol while Sodium Thiosulfate Pentahydrate is 0.2059 kJ/mol. Therefore, Sodium Chloride could store more energy on a per gram basis.
5 0
3 years ago
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