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Brilliant_brown [7]
3 years ago
9

What is an adaptive organ of duck​

Chemistry
2 answers:
leva [86]3 years ago
7 0

Answer:

The adaptive organ of duck is webbed feet.

Explanation:

Duck's webbed feet are designed like paddles to provide more surface area to help them swim.

Vera_Pavlovna [14]3 years ago
6 0

the webbed feet

Explanation:

You might be interested in
N2 + 3H2 - 2NH3
vladimir1956 [14]

The number of mole of nitrogen gas, N₂, needed to produce 150 g of ammonia, NH₃ is 4.41 moles

<h3>How to determine the mole of NH₃ produced </h3>
  • Mass of NH₃ = 150 g
  • Molar mass of NH₃ = 14 + (3×1) = 17 g/mol
  • Mole of NH₃ =?

Mole = mass /molar mass

Mole of NH₃ = 150 / 17

Mole of NH₃ = 8.82 moles

<h3>How to determine the mole of N₂ needed </h3>

Balanced equation

N₂ + 3H₂ —> 2NH₃

From the balanced equation above,

2 moles of NH₃ were produced by 1 mole of N₂.

Therefore,

8.82 moles of NH₃ will be produced by = 8.82 / 2 = 4.41 moles of N₂.

Thus, 4.41 moles of N₂ is  needed for the reaction.

Learn more about stoichiometry:

brainly.com/question/14735801

4 0
2 years ago
Suppose a student completes an experiment with an average value of 2.6 mL and a calculated standard deviation of 0.80 mL. What i
DaniilM [7]

Answer:

Explanation:

1 standard deviation range will look like: [average - SD, average + SD]

Here the miximum value will be: average - SD = 2.6 - 0.80 = 1.80 ml

and the maximum value will be: average + SD = 2.6 + 0.80 = 3.40ml

7 0
3 years ago
When a strip of magnesium metal is touched to a flame, a bright light and a whitish substance are produced. Why is ghe burning o
Kipish [7]
It changes the chemical composition of the magnesium into something else (whitish substance)
3 0
3 years ago
Choose the aqueous solution below with the lowest freezing point. These are all solutions of nonvolatile solutes and you should
atroni [7]

Answer:

(NH_4)_3PO_4 0.075 m solution has the lowest freezing point.

Explanation:

Depression in freezing point is given by:

\Delta T_f=T-T_f

\Delta T_f=K_f\times m

\Delta T_f=iK_f\times \frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Mass of solvent in Kg}}

where,

\Delta T_f =Depression in freezing point

K_f = Freezing point constant of solvent

1 - van't Hoff factor

m = molality

According question, molality of all the solutions are same and are in prepared with same solvent. So, values of molality and K_f will remain the same and will not effect the freezing point of the solution.

The lowering in freezing point will now depend upon van't Hoff factors of the solutions. Higher the value of van'Hoff factor more will be the lowering in freezing point of the solution.

The van't Hoff factor of KNO_2 solution = i_1=2

The van't Hoff factor of LiCN solution = i_2=2

The van't Hoff factor of (NH_4)_3PO_4 solution = i_3=4

The van't Hoff factor of NaI solution = i_4=2

The van't Hoff factor of NaBrO_3 solution = i_5=2

The solution of ammonium phosphate has the highest values of van't Hoff factor which will result in maximum lowering of the freezing point of the solution.

Hence,(NH_4)_3PO_4 0.075 m solution has the lowest freezing point.

4 0
3 years ago
Read 2 more answers
How many moles of ethylene (C2H4) can react with 12.9 liters of oxygen gas at 1.2 atmospheres and 297 Kelvin? C2H4(g) + 3O2(g) y
7nadin3 [17]
1) Convert 12.9 liters of Oxygen to mol at the given conditions:

PV = nRT ⇒ n = PV/RT

n = [1.2atm*12.9 l] / [0.082 atm l /K mol * 297K]

n = 0.636 mol of O2

2) use the stoichiometry derived from the balanced chemical equation

 1mol C2H4 / 3  mol O2 =  x mol C2H4 / 0.636 mol O2

x = 0.636 / 3 mol O2 = 0.212 mol O2.

Answer: 0.212 mol O2
5 0
3 years ago
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