Her mean score for the first 7 holes is around 2 because 4+11=15 and 15 divided by 7 equals a little over 2
Answer:
a. 97.72%
Step-by-step explanation:
The weights of boxes follows normal distribution with mean=28 ounce and standard deviation=0.9 ounces.
a. We have to calculated the percentage of the boxes that weighs more than 26.2 ounces.
Let X be the weight of boxes. We have to find P(X>26.2).
The given mean and Standard deviations are μ=28 and σ=0.9.
P(X>26.2)= P((X-μ/σ )> (26.2-28)/0.9)
P(X>26.2)= P(z> (-1.8/0.9))
P(X>26.2)= P(z>-2)
P(X>26.2)= P(0<z<∞)+P(-2<z<0)
P(-2<z<0) is computed by looking 2.00 in table of areas under the unit normal curve.
P(X>26.2)=0.5+0.4772
P(X>26.2)= 0.9772
Thus, the percent of the boxes weigh more than 26.2 ounces is 97.72%
Answer:
a(n) = 7*2^(n - 1)
Step-by-step explanation:
The first term of the given geometric sequence, 7, 14, 28, 56, 112, ... , is 7, and the common ratio is 2. Each new term is twice the previous term.
Thus the general formula for the geometric sequence becomes
a(n) = 7*2^(n - 1).
As a check, let's see whether this formula correctly predicts the fourth term (56): Here n = 4, and so a(4) = 7*2^(4 - 1) = 7*2^3 = 7*8 = 56. Yes.
If you're looking for the area, it is 480 cm squared.
Answer:
dodecagon
Step-by-step explanation:
