Answer:
There would be 3 temperature changes and 2 phase transitions
Explanation:
The temperature of the material would first increase from T0 to Tm (its melting point)- This is one temperature change.
It would the change from solid to liquid at its melting point Tm.- This is one phase transition.
Its temperature would then increase from its melting point Tm to its boiling point Tv -This is another temperature change.
It would then change from liquid to gas at its boiling point Tv - This is another phase transition.
Finally, its temperature would then increase from its boiling point to T(f) - This is the third temperature change.
So, there would be 3 temperature changes and 2 phase transitions
I don't think it's any of the above. Because there is two double carbon bonds and it belongs to an alkene, it should be an ethene molecule.
1. B, helium
2. B, carbs-lipids-nucleic acids-proteins
hope I helped
Answer:
The activation energy for this reaction = 23 kJ/mol.
Explanation:
Using the expression,
Where,
is the activation energy
R is Gas constant having value = 8.314×10⁻³ kJ / K mol
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
So,
T = (280 + 273.15) K = 553.15 K
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
So,
T = (376 + 273.15) K = 649.15 K
So,
<u>The activation energy for this reaction = 23 kJ/mol.</u>