1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
zhuklara [117]
3 years ago
9

If a container holds 1mol of hydrogen, 2.5mol of helium, and 2mol of oxygen at a total pressure of 4atm, what is the partial pre

ssure of the oxygen gas?
Chemistry
2 answers:
nlexa [21]3 years ago
7 0

Answer:

Partial pressure O₂  = 1.78 atm

Explanation:

We can apply the mole fraction to solve the question:

Moles of gas / Total moles = Partial pressure of gas / Total pressure

Total moles = 1 H₂ + 2.5 He + 2O₂ = 4.5 moles

2 mol O₂ / 4.5 mol = Partial pressure O₂ / 4 atm

(2 mol O₂ / 4.5 mol ) . 4 atm = Partial pressure O₂  → 1.78 atm

Reika [66]3 years ago
7 0

Answer:

The partial pressure of oxygen is 1.45 atm

Explanation:

Step 1: Data given

Number of moles of hydrogen = 1 mol

Number of moles of helium = 2.5 mol

Number of moles of oxygen = 2 mol

Total pressure = 4 atm

Step 2: Calcualte total number of moles

Total number of moles = number of moles of hydrogen + number of moles of helium + number of moles of oxygen = 1 + 2.5 + 2 = 5.5 mol

Step 3: Calculate mol fraction of oxygen

Mol fraction oxygen = 2 mol / 5.5 mol = 0.3636

Step 4: Calculate partial pressure of oxygen

Partial pressure of oxygen = mol fraction of oxygen * total pressure

Partial pressure of oxygen = 0.3636 * 4 atm = 1.45 atm

The partial pressure of oxygen is 1.45 atm

You might be interested in
What is the half-life of a 12 g sample of radioisotope that decayed to 6 g in 28
Charra [1.4K]

Answer:

A. 28 years

Explanation:

Applying,

R = R'(2ᵃ/ⁿ).............. Equation 1

Where R = Original sample, R' = Sample left after decay, a = Total time taken to decay, n = half life.

From the question,

Given: R = 12 g, R' = 6 g, a = 28 years.

Substitute into equation 1 and solve for n

12 = 6(2²⁸/ⁿ)

12/6 = 2²⁸/ⁿ

2²⁸/ⁿ = 2

Equation the base,

28/n = 1

n = 28 years.

Hence the half-life is 28 years

4 0
3 years ago
Gravitational forces exerted on any two____in the universe
OleMash [197]

Answer:-

Gravitational forces exerted on any two <em><u>bodies</u></em> in the universe

Hope it helps you...

✅

6 0
3 years ago
Be sure to answer all parts. Consider the reaction A + B → Products From the following data obtained at a certain temperature, d
worty [1.4K]

Answer : The order of reaction with respect to A is, first order reaction.

The order of reaction with respect to B is, zero order reaction.

The overall order of reaction is, first order reaction.  

Explanation :

Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

For the given chemical equation:

A+B\rightarrow Products

Rate law expression for the reaction:

\text{Rate}=k[A]^a[B]^b

where,

a = order with respect to A

b = order with respect to B

Expression for rate law for first observation:

3.20\times 10^{-1}=k(1.50)^a(1.50)^b ....(1)

Expression for rate law for second observation:

3.20\times 10^{-1}=k(1.50)^a(2.50)^b ....(2)

Expression for rate law for third observation:

6.40\times 10^{-1}=k(3.00)^a(1.50)^b ....(3)

Dividing 1 from 2, we get:

\frac{3.20\times 10^{-1}}{3.20\times 10^{-1}}=\frac{k(1.50)^a(2.50)^b}{k(1.50)^a(1.50)^b}\\\\1=1.66^b\\b=0

Dividing 1 from 3, we get:

\frac{6.40\times 10^{-1}}{3.20\times 10^{-1}}=\frac{k(3.00)^a(1.50)^b}{k(1.50)^a(1.50)^b}\\\\2=2^a\\a=1

Thus, the rate law becomes:

\text{Rate}=k[A]^1[B]^0

\text{Rate}=k[A]

Thus,

The order of reaction with respect to A is, first order reaction.

The order of reaction with respect to B is, zero order reaction.

The overall order of reaction is, first order reaction.

7 0
3 years ago
Does an astronaut have more mass on earth then space? why or why not?
katovenus [111]

Answer:

No

Explanation:

No, his mass remains the same no matter where he is in the universe.

But then again the moon has less gravitational pull, therefore your weight and mass will be smaller in space and on the moon than on earth

I hope this was helpful! ;)

3 0
3 years ago
An interpenetrating primitive cubic structure like that of CsCl with anions in the corners has an edge length of 664 pm. If the
san4es73 [151]

Answer:

the ionic radius of the anion r^- = 312.52 \ pm

Explanation:

From the diagram shown below :

The anion Cl^- is located at the corners

The cation Cs^+ is located at the body center

The Body diagonal length =  \sqrt{3 \ a }

∴ 2 \ r^+ \ + 2r^- \ = \sqrt{3 \ a}  \\ \\ r^+ +r^- = \frac{\sqrt{3}}{2} a

Given that :

\frac{r^+}{r^-} =0.84   (i.e the  ratio of the ionic radius of the cation to the ionic radius of

                 the anion )

0.84r^- \ + r^- \ = \frac{\sqrt{3}}{2}a  \\ \\  1.84 r^- = \frac{3}{2}a \\ \\ r^- = \frac{\sqrt{3}}{2*1.84}a

Also ; a =  664 pm

Then :

r^- = \frac{\sqrt{3} }{2*1.84}*664 \ pm\\ \\ r^- = 312.52 \ pm

Therefore,  the ionic radius of the anion r^- = 312.52 \ pm

4 0
3 years ago
Other questions:
  • In a electrolytic cell, where does oxidation occur
    9·2 answers
  • How many CL are in a L
    13·1 answer
  • 2) What is the concentration of NaCl in a solution prepared by diluting 56.98 ml of 0.5894 M stock
    5·1 answer
  • The two stages of cellular respiration.
    12·1 answer
  • What is 4.50+3.4+12.09 ?​
    14·2 answers
  • A current of 2.50 amps is passed through an electrolytic cell containing a solution of M(NO3)2, where M represents an unidentifi
    11·1 answer
  • What is the SI unit for force?
    10·1 answer
  • B) Sodium + Oxygen Sodium Oxide + Type of Reaction :
    7·1 answer
  • 20 ml of a solution of sucrose contains 850 mg of sucrose. What is the weight/volume percentage concentration of this solution i
    6·1 answer
  • ______Is analyzed by qualitative methods
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!