The answer is Rr and rr.
We know:
r - recessive allele
R - dominant allele
RR - dominant homozygote with red eyes
Rr - heterozygote with red eyes (since one dominant allele R can mask recessive allele r)
rr - recessive homozygote with sepia eyes
Heterozygote Rr can give to the offspring either dominant allele R or recessive allele r. Recessive homozygote rr can give to the offspring only recessive allele r (take a look at the uploaded image of Punnett square).
After crossing the parents:
Parents: Rr x rr
Offspring: Rr rr Rr rr
So:
2 out of 4 offspring will be with heterozygous with red eyes Rr: 2/4 = 0.5 = 50%
2 out of 4 offspring will be with homozygous with sepia eyes rr: 2/4 = 0.5 = 50%
Answer:
Either the sun or anything that can give light.
Explanation:
The correct answer for this question would be the fourth option. Deletion of genes around the centromere is considered a pericentric inversion. The Pericentric inversions include the centromere and there is a break point in each arm. <span>Deletions and duplications occur during crossing over during the inversion which results in recombination in two loops. </span>
Here is the work for the punnet square problem in the top. If you have any questions just ask me!