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Vadim26 [7]
3 years ago
11

What is fraction 5/33 in a decimal form

Mathematics
2 answers:
tigry1 [53]3 years ago
5 0
0.15 but with a line over the 15
SVEN [57.7K]3 years ago
4 0

Answer:

0.15 etc.

Step-by-step explanation:

You might be interested in
What are the restrictions for y <br> X=10/5+y
Naya [18.7K]

Answer:

y\ne-5

Step-by-step explanation:

So you have the equation:

  x=\frac{10}{5+y}. As you may know, you cannot divide by 0, so y has to be restricted in a way that the denominator is never equal to 0. So to find when y makes the denominator 0, simply set the denominator equal to 0, and solve for y. This gives you the equation: 5+y = 0, y=-5. So the y value CANNOT be equal to -5. Because it makes the denominator 0. so y\ne-5 would be the restriction.

7 0
2 years ago
You are a lifeguard and spot a drowning child 60 meters along the shore and 40 meters from the shore to the child. You run along
sukhopar [10]

Answer:

The lifeguard should run across the shore a distance of 48.074 m before jumpng into the water in order to minimize the time to reach the child.

Step-by-step explanation:

This is a problem of optimization.

We have to minimize the time it takes for the lifeguard to reach the child.

The time can be calculated by dividing the distance by the speed for each section.

The distance in the shore and in the water depends on when the lifeguard gets in the water. We use the variable x to model this, as seen in the picture attached.

Then, the distance in the shore is d_b=x and the distance swimming can be calculated using the Pithagorean theorem:

d_s^2=(60-x)^2+40^2=60^2-120x+x^2+40^2=x^2-120x+5200\\\\d_s=\sqrt{x^2-120x+5200}

Then, the time (speed divided by distance) is:

t=d_b/v_b+d_s/v_s\\\\t=x/4+\sqrt{x^2-120x+5200}/1.1

To optimize this function we have to derive and equal to zero:

\dfrac{dt}{dx}=\dfrac{1}{4}+\dfrac{1}{1.1}(\dfrac{1}{2})\dfrac{2x-120}{\sqrt{x^2-120x+5200}} \\\\\\\dfrac{dt}{dx}=\dfrac{1}{4} +\dfrac{1}{1.1} \dfrac{x-60}{\sqrt{x^2-120x+5200}} =0\\\\\\  \dfrac{x-60}{\sqrt{x^2-120x+5200}} =\dfrac{1.1}{4}=\dfrac{2}{7}\\\\\\ x-60=\dfrac{2}{7}\sqrt{x^2-120x+5200}\\\\\\(x-60)^2=\dfrac{2^2}{7^2}(x^2-120x+5200)\\\\\\(x-60)^2=\dfrac{4}{49}[(x-60)^2+40^2]\\\\\\(1-4/49)(x-60)^2=4*40^2/49=6400/49\\\\(45/49)(x-60)^2=6400/49\\\\45(x-60)^2=6400\\\\

x

As d_b=x, the lifeguard should run across the shore a distance of 48.074 m before jumpng into the water in order to minimize the time to reach the child.

7 0
3 years ago
Use the list method to write "the perfect square integers between 1 and 80 inclusive".
Len [333]
<span> all of our square numbers from 1 to 80 are 1, 4, 9, 16, 25, 36, 49, 64. </span>
5 0
3 years ago
Read 2 more answers
( CORRECT ANSWER GETS BRAINLIEST AND FULL RATINGS !!!)
ozzi

Answer:

a . 1/13      

Step-by-step explanation:

6 0
3 years ago
Pls help its a pretty easy question and quick points
diamong [38]
I’m not sure but it’s either going to be b or c
7 0
3 years ago
Read 2 more answers
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